HESI RN
Leadership HESI
1. The nurse is caring for a client with hyperaldosteronism. Which of the following laboratory results would the nurse expect?
- A. Hypokalemia
- B. Hypernatremia
- C. Hyperkalemia
- D. Hypocalcemia
Correct answer: A
Rationale: In hyperaldosteronism, there is an excess of aldosterone production, leading to increased sodium retention and potassium excretion by the kidneys. This results in hypokalemia (low potassium levels). Therefore, the correct answer is hypokalemia (Choice A). Hypernatremia (Choice B) is an incorrect choice as hyperaldosteronism primarily affects potassium and not sodium levels. Hyperkalemia (Choice C) is also incorrect because hyperaldosteronism causes potassium excretion, leading to low levels. Hypocalcemia (Choice D) is not typically associated with hyperaldosteronism; instead, it is more related to conditions affecting calcium regulation.
2. During a physical assessment of a client with type 2 DM, a nurse notes the following findings: fasting blood glucose of 120 mg/dl, temperature of 101°F, pulse 88 bpm, respirations 22/min, and BP 140/84 mmHg. Which finding should concern the nurse the most?
- A. Pulse
- B. BP
- C. Respiration
- D. Temperature
Correct answer: D
Rationale: The correct answer is 'Temperature.' A temperature of 101°F indicates a fever, which can be a sign of infection. In individuals with diabetes, infections can lead to significant complications and affect blood glucose control. Monitoring and addressing infections promptly are crucial in individuals with diabetes to prevent worsening of their condition. Choice A, 'Pulse,' is within the normal range (60-100 bpm) and does not indicate an immediate concern. Choice B, 'BP,' while slightly elevated, is not as acutely concerning as an elevated temperature in this scenario. Choice C, 'Respiration,' falls within the normal range (12-20 breaths/min) and is not the most concerning finding among the options provided.
3. A client with hyperthyroidism is prescribed methimazole. The nurse should instruct the client that the purpose of this medication is to:
- A. Decrease thyroid hormone production
- B. Increase thyroid hormone production
- C. Suppress the immune system
- D. Prevent thyroid storm
Correct answer: A
Rationale: The correct answer is A: Decrease thyroid hormone production. Methimazole works by inhibiting the synthesis of thyroid hormones, specifically by blocking the enzyme responsible for this process. By reducing the production of thyroid hormones, methimazole helps to normalize the elevated levels seen in hyperthyroidism. Choices B, C, and D are incorrect. Choice B, 'Increase thyroid hormone production,' is inaccurate as methimazole actually decreases thyroid hormone production. Choice C, 'Suppress the immune system,' is unrelated to the mechanism of action of methimazole. Choice D, 'Prevent thyroid storm,' is not the primary purpose of methimazole; while it may help prevent worsening of hyperthyroidism, its main action is to reduce thyroid hormone levels.
4. A client with hypothyroidism is at risk for which of the following complications?
- A. Thyroid storm
- B. Myxedema coma
- C. Cushing's syndrome
- D. Diabetic ketoacidosis
Correct answer: B
Rationale: Myxedema coma is a severe, life-threatening complication that can occur in individuals with untreated or inadequately treated hypothyroidism. It is characterized by extreme hypothyroidism leading to decreased mental status, hypothermia, bradycardia, and respiratory depression. Thyroid storm (Choice A) is a severe complication of hyperthyroidism, not hypothyroidism. Cushing's syndrome (Choice C) results from prolonged exposure to high levels of cortisol, not related to hypothyroidism. Diabetic ketoacidosis (Choice D) is a complication of uncontrolled diabetes, not directly associated with hypothyroidism.
5. Nurse Perry is caring for a female client with type 1 diabetes mellitus who exhibits confusion, light-headedness, and aberrant behavior. The client is still conscious. The nurse should first administer:
- A. I.M. or subcutaneous glucagon.
- B. I.V. bolus of dextrose 50%.
- C. 15 to 20 g of a fast-acting carbohydrate such as orange juice.
- D. 10 U of fast-acting insulin.
Correct answer: C
Rationale: For a conscious client with hypoglycemia, the initial treatment should involve administering 15 to 20 g of a fast-acting carbohydrate, such as orange juice. This helps rapidly raise the client's blood glucose levels. Choices A and D are incorrect as administering glucagon or fast-acting insulin is not the first-line treatment for hypoglycemia in a conscious client. Choice B, an I.V. bolus of dextrose 50%, is a more invasive and aggressive intervention that is not typically indicated for a conscious client with hypoglycemia.
Similar Questions
Access More Features
HESI RN Basic
$69.99/ 30 days
- 50,000 Questions with answers
- All HESI courses Coverage
- 30 days access @ $69.99
HESI RN Premium
$149.99/ 90 days
- 50,000 Questions with answers
- All HESI courses Coverage
- 30 days access @ $149.99