Nursing Elites

1. A client with Diabetes Insipidus (DI) is being cared for by a nurse. Which data warrants the most immediate intervention by the nurse?

• A. Serum sodium of 185 mEq/L (185 mmol/L)
• B. Dry skin with poor skin turgor
• C. Apical rate of 110 beats per minute
• D. Polyuria and excessive thirst

Correct answer: A

Rationale: A serum sodium level of 185 mEq/L (185 mmol/L) is dangerously high and indicates severe dehydration, requiring immediate intervention to prevent neurological damage. The other options are not as critical as high serum sodium levels, which can lead to serious complications such as seizures, coma, and death if not promptly addressed. Dry skin with poor skin turgor and polyuria with excessive thirst are common findings in clients with Diabetes Insipidus and should be managed but do not pose an immediate threat to the client's life. An apical heart rate of 110 beats per minute may indicate tachycardia, which could be related to dehydration but is not as urgent as addressing the severe hypernatremia.

2. The nurse instructs the unlicensed nursing personnel (UAP) on how to provide oral hygiene for clients who cannot perform this task for themselves. Which of the following techniques should the nurse tell the UAP to incorporate into the client's daily care?

• A. Assess the oral cavity each time mouth care is given and record observations.
• B. Use a soft toothbrush to brush the client's teeth after each meal.
• C. Swab the client's tongue, gums, and lips with a soft foam applicator every 2 hours.
• D. Rinse the client's mouth with mouthwash several times a day.

Correct answer: B

Rationale: The correct technique to incorporate into the client's daily care for oral hygiene is to use a soft toothbrush to brush the client's teeth after each meal. This helps in maintaining oral hygiene for clients who cannot perform this task themselves. Choice A is incorrect because assessing the oral cavity each time mouth care is given is important but not the technique to incorporate into daily care. Choice C is incorrect as swabbing the tongue, gums, and lips every 2 hours may not be necessary for daily care. Choice D is incorrect as rinsing the client's mouth with mouthwash several times a day may not be suitable for all clients and is not a standard recommendation for daily oral care.

3. The client has been managing angina episodes with nitroglycerin. Which of the following indicates the drug is effective?

• A. Decreased chest pain.
• B. Increased blood pressure.
• C. Decreased blood pressure.
• D. Decreased heart rate.

Correct answer: A

Rationale: The correct answer is A: Decreased chest pain. Nitroglycerin is a vasodilator that works by decreasing myocardial oxygen consumption, which helps to reduce chest pain caused by angina. Therefore, a reduction in chest pain is a positive indicator of the drug's effectiveness. Choices B, C, and D are incorrect because nitroglycerin does not typically increase blood pressure or heart rate; instead, it often causes a decrease in blood pressure due to vasodilation and may cause a reflex tachycardia (increased heart rate) as a compensatory response to lowered blood pressure.

4. The client is being educated by the nurse on home blood glucose monitoring. Which of the following blood glucose measurements indicates hypoglycemia?

• A. 59 mg/dL (3.3 mmol/L)
• B. 75 mg/dL (4.2 mmol/L)
• C. 108 mg/dL (6 mmol/L)
• D. 119 mg/dL (6.6 mmol/L)

Correct answer: A

Rationale: A blood glucose level of 59 mg/dL (3.3 mmol/L) is considered hypoglycemia, which is an abnormally low blood sugar level. This level requires immediate attention as it can lead to symptoms such as confusion, shakiness, and even loss of consciousness if left untreated. Choices B, C, and D have blood glucose levels within the normal range or slightly higher, indicating euglycemia or normal blood sugar levels, and not hypoglycemia.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

• A. Failing eyesight causing an unsafe environment.
• B. Renal osteodystrophy due to chronic renal failure.
• C. Osteoporosis due to hormonal changes.
• D. Cardiovascular changes leading to small strokes impairing mental acuity.

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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