HESI RN
HESI Medical Surgical Test Bank
1. In the change-of-shift report, the nurse is told that a client has a Stage 2 pressure ulcer. Which ulcer appearance is most likely to be observed?
- A. Shallow open ulcer with a red-pink wound bed.
- B. A deep pocket of infection and necrotic tissues.
- C. An area of erythema that is painful to touch.
- D. Visible subcutaneous tissue with sloughing.
Correct answer: A
Rationale: A Stage 2 pressure ulcer typically presents as a shallow open ulcer with a red-pink wound bed. This appearance is characteristic of a Stage 2 pressure ulcer where there is partial thickness skin loss involving the epidermis and possibly the dermis. Choice B, a deep pocket of infection and necrotic tissues, is more indicative of a Stage 3 or Stage 4 pressure ulcer where the ulcer extends into deeper tissue layers. Choice C, an area of erythema that is painful to touch, is more commonly seen in early-stage pressure ulcers such as Stage 1. Choice D, visible subcutaneous tissue with sloughing, is characteristic of a more severe stage of pressure ulcer beyond Stage 2.
2. A healthcare professional is reading the chest x-ray report of a client who has just been intubated. The report states that the tip of the endotracheal tube lies 1 cm above the carina. The healthcare professional interprets that the tube is positioned above:
- A. The first tracheal cartilaginous ring
- B. The point where the larynx connects to the trachea
- C. The bifurcation of the right and left main stem bronchi
- D. The area connecting the oropharynx to the laryngopharynx
Correct answer: C
Rationale: The carina is a cartilaginous ridge that separates the openings of the two main stem (right and left) bronchi. If an endotracheal tube is inserted past the carina, the tube will enter the right main stem bronchus due to the natural curvature of the airway. This positioning is dangerous as only the right lung will be ventilated. It can be identified as only the right lung will have breath sounds and rise and fall with ventilation. Choices A, B, and D are incorrect as they do not relate to the specific anatomical landmark mentioned in the scenario.
3. A client who is receiving chemotherapy asks the nurse, 'Why is so much of my hair falling out each day?' Which response by the nurse best explains the reason for alopecia?
- A. 'Chemotherapy affects the cells of the body that grow rapidly, both normal and malignant.'
- B. 'Alopecia is a common side effect you will experience during long-term steroid therapy.'
- C. 'Your hair will grow back completely after your course of chemotherapy is completed.'
- D. 'The chemotherapy causes permanent alterations in your hair follicles that lead to hair loss.'
Correct answer: A
Rationale: The correct answer is A: 'Chemotherapy affects the cells of the body that grow rapidly, both normal and malignant.' Chemotherapy targets rapidly dividing cells, which include not only cancer cells but also healthy cells like those in hair follicles. This leads to alopecia (hair loss) as a common side effect. Choice B is incorrect as alopecia is primarily associated with chemotherapy and not long-term steroid therapy. Choice C is incorrect because while hair may grow back after chemotherapy, it may not always be to the same extent or thickness. Choice D is incorrect as chemotherapy-induced hair loss is often temporary and reversible, not permanent alterations in hair follicles.
4. A client is experiencing diarrhea. For which acid-base disorder should the nurse assess the client?
- A. Metabolic acidosis
- B. Metabolic alkalosis
- C. Respiratory acidosis
- D. Respiratory alkalosis
Correct answer: A
Rationale: When a client experiences diarrhea, the loss of bicarbonate-rich fluids from the body leads to a decrease in the bicarbonate levels in the blood, resulting in metabolic acidosis. Metabolic alkalosis (choice B) is characterized by an increase in bicarbonate levels, which is not typically associated with diarrhea. Respiratory acidosis (choice C) is caused by retention of carbon dioxide, while respiratory alkalosis (choice D) results from excessive exhalation of carbon dioxide, neither of which are directly related to diarrhea. Therefore, the correct answer is metabolic acidosis (choice A) in the context of diarrhea.
5. A nurse reviews a female client’s laboratory results. Which result from the client’s urinalysis should the nurse recognize as abnormal?
- A. pH 5.6
- B. Ketone bodies present
- C. Specific gravity of 1.020
- D. Clear and yellow color
Correct answer: B
Rationale: The correct answer is B: Ketone bodies present. Ketone bodies in urine indicate abnormal metabolism, specifically the incomplete breakdown of fatty acids. Normally, there should be no ketones present in urine. Ketone bodies are produced when the body uses fat sources instead of glucose for cellular energy. A pH range between 4.6 and 8, a specific gravity between 1.005 and 1.030, and clear yellow color in urine are considered normal findings for a female client’s urinalysis. Therefore, options A, C, and D are within normal ranges and not indicative of abnormal results in the urinalysis.
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