Nursing Elites

1. In the change-of-shift report, the nurse is told that a client has a Stage 2 pressure ulcer. Which ulcer appearance is most likely to be observed?

• A. Shallow open ulcer with a red-pink wound bed.
• B. A deep pocket of infection and necrotic tissues.
• C. An area of erythema that is painful to touch.
• D. Visible subcutaneous tissue with sloughing.

Correct answer: A

Rationale: A Stage 2 pressure ulcer typically presents as a shallow open ulcer with a red-pink wound bed. This appearance is characteristic of a Stage 2 pressure ulcer where there is partial thickness skin loss involving the epidermis and possibly the dermis. Choice B, a deep pocket of infection and necrotic tissues, is more indicative of a Stage 3 or Stage 4 pressure ulcer where the ulcer extends into deeper tissue layers. Choice C, an area of erythema that is painful to touch, is more commonly seen in early-stage pressure ulcers such as Stage 1. Choice D, visible subcutaneous tissue with sloughing, is characteristic of a more severe stage of pressure ulcer beyond Stage 2.

2. Why is the combination drug trimethoprim-sulfamethoxazole (TMP-SMX) necessary?

• A. To broaden the antibacterial spectrum.
• B. To decrease bacterial resistance.
• C. To improve the taste.
• D. To minimize toxic effects.

Correct answer: B

Rationale: The correct answer is B: To decrease bacterial resistance. Trimethoprim-sulfamethoxazole (TMP-SMX) is a combination drug used to prevent bacterial resistance to sulfonamides. It works by targeting different steps in the bacterial metabolic pathway, making it harder for bacteria to develop resistance. Choice A is incorrect because the combination does not broaden the antibacterial spectrum; instead, it enhances effectiveness against specific bacteria. Choice C is incorrect as taste improvement is not the primary reason for combining these drugs. Choice D is incorrect because while combination therapy can sometimes help minimize toxic effects, the primary purpose in this case is to address bacterial resistance.

3. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

• A. Failing eyesight causing an unsafe environment.
• B. Renal osteodystrophy due to chronic renal failure.
• C. Osteoporosis due to hormonal changes.
• D. Cardiovascular changes leading to small strokes impairing mental acuity.

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

4. The client admitted with peripheral vascular disease (PVD) asks the nurse why her legs hurt when she walks. The nurse bases a response on the knowledge that the main characteristic of PVD is:

• A. Decreased blood flow.
• B. Increased blood flow.
• C. Slow blood flow.
• D. Thrombus formation.

Correct answer: A

Rationale: The correct answer is A: 'Decreased blood flow.' In peripheral vascular disease (PVD), there is a narrowing or blockage of blood vessels, leading to reduced blood flow to the extremities. This decreased blood flow results in inadequate oxygen supply to the muscles, causing pain, especially during physical activity when oxygen demand increases. Choice B, 'Increased blood flow,' is incorrect because PVD is characterized by impaired blood circulation rather than increased flow. Choice C, 'Slow blood flow,' is not precise as PVD involves a more significant reduction in blood flow. Choice D, 'Thrombus formation,' is related to the formation of blood clots within vessels, which can be a complication of PVD but is not its main characteristic.

5. What is the most common side effect of diuretics such as furosemide (Lasix)?

• A. Hypokalemia.
• B. Hyperkalemia.
• C. Hypernatremia.
• D. Hyponatremia.

Correct answer: A

Rationale: The correct answer is 'Hypokalemia.' Diuretics like furosemide increase the excretion of potassium, leading to hypokalemia as a common side effect. Hyperkalemia (choice B) is the opposite condition characterized by high potassium levels, which is not typically associated with furosemide use. Hypernatremia (choice C) is increased sodium levels, while hyponatremia (choice D) is decreased sodium levels, neither of which are the most common side effects of furosemide. Therefore, choice A is the best answer.

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