Nursing Elites

1. A patient is being treated for shock after a motor vehicle accident. The provider orders 6% dextran 75 to be given intravenously. The nurse should expect which outcome as the result of this infusion?

• A. Decreased urine output
• B. Improved blood oxygenation
• C. Increased interstitial fluid
• D. Stabilization of heart rate and blood pressure

Correct answer: D

Rationale: 6% Dextran 75 is a high molecular-weight colloidal solution used to treat shock from burns or trauma. Colloids like 6% dextran 75 are plasma expanders that help increase blood volume, leading to improved heart rate and blood pressure stabilization. The infusion of plasma expanders does not typically decrease urine output. It primarily aims to stabilize circulation rather than affect blood oxygenation or increase interstitial fluid levels.

2. The nurse is caring for a patient who is receiving oral potassium chloride supplements. The nurse notes that the patient has a heart rate of 120 beats per minute and has had a urine output of 200 mL in the past 12 hours. The patient reports abdominal cramping. Which action will the nurse take?

• A. Contact the provider to request an order for serum electrolytes.
• B. Encourage the patient to consume less fluids.
• C. Report symptoms of hyperkalemia to the provider.
• D. Request an order to increase the patient’s potassium dose.

Correct answer: A

Rationale: Oliguria, tachycardia, and abdominal cramping are signs of hyperkalemia, so the nurse should request an order for serum electrolytes to assess the patient's potassium levels. Encouraging the patient to consume less fluids would not address the underlying issue of potential hyperkalemia. Reporting symptoms of hyperkalemia to the provider is not as proactive as directly requesting serum electrolytes. Increasing the patient's potassium dose would worsen hyperkalemia, which is already suspected based on the symptoms presented.

3. A client is to have a transsphenoidal hypophysectomy to remove a large, invasive pituitary tumor. The nurse should instruct the client that the surgery will be performed through an incision in the:

• A. Back of the mouth.
• B. Nose.
• C. Sinus channel below the right eye.
• D. Upper gingival mucosa in the space between the upper gums and lip.

Correct answer: D

Rationale: The correct answer is D: Upper gingival mucosa in the space between the upper gums and lip. A transsphenoidal hypophysectomy involves accessing the pituitary gland through an incision in the upper gingival mucosa, providing direct access to the pituitary gland without external scars. Choices A, B, and C are incorrect because the surgery is not performed through the back of the mouth, the nose, or the sinus channel below the right eye. It is crucial for the client to understand the specific location of the incision to ensure accurate preoperative education and expectations.

4. A client has undergone insertion of a permanent pacemaker. When developing a discharge teaching plan, the nurse writes a goal of, 'The client will verbalize symptoms of pacemaker failure.' Which symptoms are most important to teach the client?

• A. Facial flushing.
• B. Fever.
• C. Pounding headache.
• D. Feelings of dizziness.

Correct answer: D

Rationale: The correct answer is 'D: Feelings of dizziness.' Feelings of dizziness may occur as a result of a decreased heart rate, leading to decreased cardiac output, which can be an indication of pacemaker failure. Teaching the client to recognize symptoms of decreased cardiac output, like dizziness, is crucial for early detection of pacemaker malfunction. Choices A, B, and C are less specific to pacemaker failure and are not commonly associated with this condition. Facial flushing, fever, and pounding headache are not typical signs of pacemaker failure and are not directly related to cardiac output, making them less relevant for teaching the client about pacemaker failure.

5. The client is being educated by the nurse on home blood glucose monitoring. Which of the following blood glucose measurements indicates hypoglycemia?

• A. 59 mg/dL (3.3 mmol/L)
• B. 75 mg/dL (4.2 mmol/L)
• C. 108 mg/dL (6 mmol/L)
• D. 119 mg/dL (6.6 mmol/L)

Correct answer: A

Rationale: A blood glucose level of 59 mg/dL (3.3 mmol/L) is considered hypoglycemia, which is an abnormally low blood sugar level. This level requires immediate attention as it can lead to symptoms such as confusion, shakiness, and even loss of consciousness if left untreated. Choices B, C, and D have blood glucose levels within the normal range or slightly higher, indicating euglycemia or normal blood sugar levels, and not hypoglycemia.

Similar Questions