Nursing Elites

1. Which client is at greatest risk for coronary artery disease?

• A. A 32-year-old female with mitral valve prolapse who quit smoking 10 years ago.
• B. A 43-year-old male with a family history of CAD and a cholesterol level of 158 (8.8 mmol/L).
• C. A 56-year-old male with an HDL of 60 (3.3 mmol/L) who takes atorvastatin.
• D. A 65-year-old female who is obese with an LDL of 188 (10.4 mmol/L).

Correct answer: D

Rationale: The 65-year-old female who is obese with a high LDL level of 188 (10.4 mmol/L) is at the greatest risk for coronary artery disease. Obesity and high LDL cholesterol levels are significant risk factors for developing coronary artery disease. While factors like mitral valve prolapse (choice A) and a family history of CAD (choice B) can contribute to the risk, they are not as significant as obesity and high LDL levels. Choice C, a 56-year-old male with high HDL and taking atorvastatin, is actually at lower risk due to the high HDL levels and being on statin therapy, which helps reduce cholesterol levels and lower the risk of coronary artery disease.

2. The nurse is obtaining a health history from a new client who has a history of kidney stones. Which statement by the client indicates an increased risk for renal calculi?

• A. Eats a vegetarian diet with cheese 2 to 3 times a day
• B. Experiences additional stress since adopting a child
• C. Jogs more frequently than usual daily routine
• D. Drinks several bottles of carbonated water daily

Correct answer: D

Rationale: The correct answer is D. Drinking several bottles of carbonated water daily may contribute to renal calculi formation due to the high mineral content. Carbonated drinks can increase the risk of kidney stones due to their high levels of phosphoric acid and caffeine, which can lead to the formation of crystals in the urine. Choices A, B, and C are less likely to directly contribute to an increased risk of renal calculi compared to the excessive consumption of carbonated water.

3. A client who experienced partial-thickness burns involving over 50% body surface area (BSA) 2 weeks ago has several open wounds and develops watery diarrhea. The client's blood pressure is 82/40 mmHg, and temperature is 96°F (36.6°C). Which action is most important for the nurse to take?

• A. Increase the room temperature.
• B. Assess the oxygen saturation.
• C. Continue to monitor vital signs.
• D. Notify the rapid response team.

Correct answer: D

Rationale: In this scenario, the client is presenting with signs of sepsis, such as hypotension, hypothermia, and a recent history of partial-thickness burns with open wounds. The development of watery diarrhea further raises suspicion for sepsis. With a blood pressure of 82/40 mmHg and a low temperature of 96°F (36.6°C), the nurse should recognize the potential for septic shock. Notifying the rapid response team is crucial in this situation as the client requires immediate intervention and management to prevent deterioration and address the underlying septic process. Increasing the room temperature (Choice A) is not the priority as the low body temperature is likely due to systemic vasodilation and not environmental factors. While assessing oxygen saturation (Choice B) is important, the client's hypotension and hypothermia take precedence. Continuing to monitor vital signs (Choice C) alone is insufficient given the critical condition of the client and the need for prompt action to address the sepsis and potential septic shock.

4. What is the most common cause of peptic ulcers?

• A. Helicobacter pylori infection
• B. NSAID use
• C. Excessive alcohol consumption
• D. Stress

Correct answer: A

Rationale: Helicobacter pylori infection is the most common cause of peptic ulcers. This bacterium can weaken the protective mucous coating of the stomach and duodenum, allowing acid to get through to the sensitive lining beneath. NSAID use (Choice B) can also cause peptic ulcers by disrupting the stomach's mucosal barrier. Excessive alcohol consumption (Choice C) and stress (Choice D) can exacerbate and contribute to ulcer formation but are not the primary cause.

5. A client who has heart failure is admitted with a serum potassium level of 2.9 mEq/L. Which action is most important for the nurse to implement?

• A. Administer 20 mEq of potassium chloride.
• B. Initiate continuous cardiac monitoring.
• C. Arrange a consultation with the dietitian.
• D. Educate about the side effects of diuretics.

Correct answer: B

Rationale: Hypokalemia, defined as a serum potassium level below the normal range of 3.5 to 5 mEq/L, can lead to changes in myocardial irritability and ECG waveform, potentially causing life-threatening dysrhythmias. Therefore, the priority action for the nurse is to initiate continuous cardiac monitoring to promptly detect any abnormal heart rhythms or ventricular ectopy. This monitoring is crucial for assessing the impact of potassium replacement therapy on the cardiac rhythm and ensuring the safety of the client. While administering potassium chloride is important for correcting the hypokalemia, it should occur after cardiac monitoring is in place. Consulting with a dietitian and educating about diuretic side effects are relevant aspects of care but are not the immediate priority in this situation where cardiac monitoring takes precedence for timely intervention.

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