Nursing Elites

1. The client is being educated by the nurse on home blood glucose monitoring. Which of the following blood glucose measurements indicates hypoglycemia?

• A. 59 mg/dL (3.3 mmol/L)
• B. 75 mg/dL (4.2 mmol/L)
• C. 108 mg/dL (6 mmol/L)
• D. 119 mg/dL (6.6 mmol/L)

Correct answer: A

Rationale: A blood glucose level of 59 mg/dL (3.3 mmol/L) is considered hypoglycemia, which is an abnormally low blood sugar level. This level requires immediate attention as it can lead to symptoms such as confusion, shakiness, and even loss of consciousness if left untreated. Choices B, C, and D have blood glucose levels within the normal range or slightly higher, indicating euglycemia or normal blood sugar levels, and not hypoglycemia.

2. In a patient with cirrhosis, which of the following lab results is most concerning?

• A. Elevated liver enzymes.
• B. Low albumin levels.
• C. Elevated bilirubin levels.
• D. Low platelet count.

Correct answer: D

Rationale: In a patient with cirrhosis, a low platelet count is the most concerning lab result. Thrombocytopenia, or low platelet count, is common in cirrhosis due to impaired platelet production in the liver. It significantly increases the risk of bleeding and can lead to serious complications such as hemorrhage. Elevated liver enzymes (Choice A) are expected in cirrhosis but may not directly indicate the severity of the disease. Low albumin levels (Choice B) are common in cirrhosis and can contribute to fluid retention but do not pose an immediate risk of bleeding. Elevated bilirubin levels (Choice C) are also expected in cirrhosis and typically indicate impaired liver function but do not directly increase the risk of bleeding as much as a low platelet count.

3. A client has a long history of hypertension. Which category of medication would the nurse expect to be ordered to avoid chronic kidney disease (CKD)?

• A. Antibiotic
• B. Histamine blocker
• C. Bronchodilator
• D. Angiotensin-converting enzyme (ACE) inhibitor

Correct answer: D

Rationale: The correct answer is D, Angiotensin-converting enzyme (ACE) inhibitor. ACE inhibitors inhibit the conversion of angiotensin I to angiotensin II, a potent vasoconstrictor. By blocking this conversion, ACE inhibitors promote vasodilation and improve perfusion to the kidneys. Additionally, ACE inhibitors block the breakdown of bradykinin and prostaglandin, further contributing to vasodilation. They also lead to increased renin and decreased aldosterone levels. These effects help in reducing blood pressure and protecting the kidneys in clients with hypertension. Antibiotics are used to fight infections, histamine blockers reduce inflammation, and bronchodilators widen the bronchi, none of which address the underlying processes involved in slowing the progression of chronic kidney disease (CKD) in hypertensive clients.

4. A client arrived to the medical-surgical unit 4 hours after a transurethral resection of the prostate (TURP). A triple-lumen catheter for continuous bladder irrigation with normal saline is infusing, and the nurse observes dark, pink-tinged outflow with blood clots in the tubing and collection bag. Which action should the nurse take?

• A. Monitoring catheter drainage
• B. Decreasing the flow rate
• C. Irrigating the catheter manually
• D. Discontinuing infusing the solution

Correct answer: C

Rationale: In this scenario, the nurse should choose option C - irrigating the catheter manually. This action can help clear the clots from the catheter and ensure proper bladder drainage. Monitoring catheter drainage (option A) alone may not address the issue of clots obstructing the flow. Decreasing the flow rate (option B) could potentially worsen clot formation. Discontinuing the infusing solution (option D) without addressing the clots first may lead to inadequate irrigation and increase the risk of complications.

5. What is the most common cause of urinary tract infections (UTIs)?

• A. Escherichia coli infection
• B. Staphylococcus aureus infection
• C. Pseudomonas aeruginosa infection
• D. Klebsiella pneumoniae infection

Correct answer: A

Rationale: Escherichia coli is the most common cause of urinary tract infections (UTIs). It is responsible for the majority of UTIs, especially in women. E. coli is a normal inhabitant of the bowel and can enter the urinary tract through the urethra, leading to infection. Staphylococcus aureus, Pseudomonas aeruginosa, and Klebsiella pneumoniae are less common causes of UTIs compared to E. coli. Staphylococcus aureus typically causes skin and soft tissue infections, Pseudomonas aeruginosa is more commonly associated with healthcare-associated infections, and Klebsiella pneumoniae is known for causing pneumonia and other respiratory infections.

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