HESI RN
Reproductive Health Exam
1. A solid ball of 12-16 cells having undergone mitotic division after fertilization is:
- A. Zygote
- B. Blastomere
- C. Morula
- D. Blastocyst
Correct answer: C
Rationale: A morula is a stage in embryonic development where a solid ball of 12-16 cells is formed after several rounds of mitotic division following fertilization. The zygote is the initial cell formed by the fusion of sperm and egg. Blastomere refers to individual cells in a developing embryo. A blastocyst is a later stage where a fluid-filled cavity forms within the embryo. Therefore, the correct answer is 'Morula.'
2. Laparoscopy uses a small instrument known as a laparoscope to:
- A. Take very detailed photographs
- B. Insert a hysteroscope for D&C
- C. Perform an abortion procedure
- D. Perform a hysterectomy
Correct answer: A
Rationale: Laparoscopy uses a small instrument known as a laparoscope to take very detailed photographs of the pelvic organs. This procedure is commonly used for diagnostic purposes, to visualize internal organs, and to perform minimally invasive surgeries. Choice B, inserting a hysteroscope for D&C, is incorrect as hysteroscopy is a different procedure used to examine the inside of the uterus, not the pelvic organs. Choice C, performing an abortion procedure, is incorrect as laparoscopy is not used for abortion. Choice D, performing a hysterectomy, is incorrect as although laparoscopy can be used in some cases for hysterectomy, its primary purpose is not for this procedure.
3. The patient about to undergo gynecological surgery is put on nil by mouth for ____ before surgery to prevent aspiration.
- A. 2-4 hours
- B. 3-5 hours
- C. 4-6 hours
- D. 5-7 hours
Correct answer: C
Rationale: Patients undergoing gynecological surgery are typically advised to be nil by mouth for 4-6 hours before the procedure to reduce the risk of aspiration. This duration allows the stomach to empty its contents, decreasing the likelihood of regurgitation and aspiration of stomach contents during surgery. Choices A, B, and D have shorter durations and may not provide sufficient time for adequate gastric emptying, increasing the risk of aspiration.
4. After fertilization, cell division occurs through a process of:
- A. Binary fission
- B. Meiosis
- C. Budding
- D. Mitosis
Correct answer: D
Rationale: After fertilization, the zygote undergoes cell division through the process of mitosis. Mitosis is the type of cell division that results in two daughter cells with the same number of chromosomes as the parent cell. Choice A, binary fission, is a form of asexual reproduction in prokaryotes, not the process that occurs after fertilization in multicellular organisms. Choice B, meiosis, is a type of cell division that leads to the formation of gametes with half the number of chromosomes, not the process that occurs after fertilization. Choice C, budding, is a form of asexual reproduction seen in some organisms like yeast, but it is not the process of cell division after fertilization.
5. Treatment for condylomata acuminata includes the following EXCEPT:
- A. Vulvectomy
- B. Podophyllin application
- C. Laser therapy
- D. Electrocautery
Correct answer: A
Rationale: The correct answer is A. Vulvectomy is not a standard treatment for condylomata acuminata, which are genital warts caused by human papillomavirus (HPV). Surgical removal of the vulva (vulvectomy) is an extreme measure and not typically indicated for treating this condition. Choices B, C, and D are valid treatments for condylomata acuminata. Podophyllin application, laser therapy, and electrocautery are commonly used to remove or destroy genital warts caused by HPV. These treatments aim to eliminate the visible warts and clear the infection.
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