Nursing Elites

1. A 68-year-old client on day 2 after hip surgery has no cardiac history but reports having chest heaviness. The first nursing action should be to:

• A. Inquire about the onset, duration, severity, and precipitating factors of the heaviness.
• B. Administer oxygen via nasal cannula.
• C. Offer pain medication for the chest heaviness.
• D. Inform the physician of the chest heaviness.

Correct answer: A

Rationale: The correct first nursing action when a client reports chest heaviness post-hip surgery is to gather more information through assessment. Inquiring about the onset, duration, severity, and precipitating factors of the heaviness is crucial to determine the cause. This approach helps the nurse to gather essential data to make an informed decision regarding the client's care. Administering oxygen (Choice B) may be indicated based on assessment findings, but it is crucial to assess first. Offering pain medication (Choice C) without further assessment is premature and may mask symptoms. Informing the physician (Choice D) should be done after a thorough assessment to provide comprehensive information for appropriate medical decision-making.

2. A client with diabetes is taking insulin lispro (Humalog) injections. The nurse should advise the client to eat:

• A. Within 10 to 15 minutes after the injection.
• B. 1 hour after the injection.
• C. At any time, because timing of meals with lispro injections is unnecessary.
• D. 2 hours before the injection.

Correct answer: A

Rationale: The correct answer is to eat within 10 to 15 minutes after the injection. Insulin lispro, also known as Humalog, is a rapid-acting insulin that starts working very quickly. Eating shortly after the injection helps match the food intake with the insulin action, reducing the risk of hypoglycemia. Choice B is incorrect because waiting 1 hour after the injection may lead to a mismatch between insulin activity and food intake. Choice C is incorrect as timing meals with lispro injections is essential to optimize glycemic control. Choice D is incorrect as eating 2 hours before the injection is not in alignment with the rapid action of insulin lispro and may lead to fluctuations in blood sugar levels.

3. A nurse reviews a client’s urinalysis report. Which finding does the nurse recognize as abnormal?

• A. pH of 6.0
• B. An absence of protein
• C. The presence of ketones
• D. Specific gravity of 1.018

Correct answer: C

Rationale: The correct answer is C. The presence of ketones in the urine is abnormal. Ketones in the urine may indicate a state of ketosis, which is commonly seen in uncontrolled diabetes, fasting, or a low-carbohydrate diet. A normal pH range of urine is 4.5 to 7.8, making a pH of 6.0 within the normal range. An absence of protein is a normal finding in urine, as proteinuria (presence of protein) is abnormal. A specific gravity of 1.018 falls within the normal range of 1.016 to 1.022. Therefore, the presence of ketones is the abnormal finding in this scenario.

4. A nurse reviews laboratory results for a client with glomerulonephritis. The client’s glomerular filtration rate (GFR) is 40 mL/min as measured by a 24-hour creatinine clearance. How should the nurse interpret this finding? (Select all that apply.)

• A. Excessive GFR
• B. Reduced GFR
• C. Fluid retention and risks for hypertension
• D. Pulmonary edema

Correct answer: B

Rationale: A GFR of 40 mL/min indicates a reduced glomerular filtration rate. In a healthy adult, the normal GFR ranges between 100 and 120 mL/min. A GFR of 40 mL/min signifies a significant reduction, leading to fluid retention and risks for hypertension and pulmonary edema due to excess vascular fluid. Choices A, C, and D are incorrect. Choice A is incorrect as a GFR of 40 mL/min is not excessive but rather reduced. Choices C and D do not directly address the interpretation of GFR but instead describe potential consequences of a reduced GFR.

5. A CD4+ lymphocyte count is performed on a client infected with HIV. The results of the test indicate a CD4+ count of 450 cells/L. The nurse interprets this test result as indicating:

• A. Improvement in the client
• B. The need for antiretroviral therapy
• C. The need to discontinue antiretroviral therapy
• D. An effective response to the treatment for HIV

Correct answer: B

Rationale: A CD4+ count of 450 cells/L is below the normal range (500-1600 cells/mcL), indicating a decline in immune function in the client. Antiretroviral therapy is recommended when the CD4+ count falls below 500 cells/mcL or below 25%, or when the client displays symptoms of HIV. Therefore, the interpretation of this test result suggests that the client requires antiretroviral therapy to manage the HIV infection. Choices A, C, and D are incorrect because a CD4+ count of 450 cells/L does not signify improvement, discontinuation of therapy, or an effective response to treatment for HIV.

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