Nursing Elites

1. Which of the following is a common cause of chronic liver disease?

• A. Alcohol abuse.
• B. Hepatitis C infection.
• C. Obesity.
• D. Smoking.

Correct answer: B

Rationale: Hepatitis C infection is a common cause of chronic liver disease due to its long-term effects on the liver. Hepatitis C can lead to liver inflammation, fibrosis, cirrhosis, and even liver cancer. Alcohol abuse can also cause liver damage, but hepatitis C infection is specifically known for its chronic impact on liver health. Obesity and smoking, while detrimental to overall health, are not typically direct causes of chronic liver disease like hepatitis C infection.

2. A healthcare professional has a prescription to collect a 24-hour urine specimen from a client. Which of the following measures should the healthcare professional take during this procedure?

• A. Keeping the specimen chilled
• B. Saving the first urine specimen collected at the start time
• C. Discarding the last voided specimen at the end of the collection time
• D. Asking the client to void, discarding the specimen, and noting the start time

Correct answer: D

Rationale: The correct answer is asking the client to void, discarding the specimen, and noting the start time. During a 24-hour urine collection, the first voided urine is discarded to ensure the test starts with an empty bladder. The specimen should be kept chilled, not at room temperature, to prevent bacterial growth. The last voided specimen is not discarded because it contributes to the total volume collected, so choice C is incorrect. Discarding the specimen and noting the start time is essential for accurate results in a timed quantitative determination like a 24-hour urine collection.

3. A nurse reviews the urinalysis of a client and notes the presence of glucose. Which action should the nurse take?

• A. Document findings and continue to monitor the client.
• B. Contact the provider and recommend a 24-hour urine test.
• C. Review the client’s recent dietary selections.
• D. Perform a capillary artery glucose assessment.

Correct answer: D

Rationale: Glucose normally is not found in the urine. The normal renal threshold for glucose is about 220 mg/dL, which means that a person whose blood glucose is less than 220 mg/dL will not have glucose in the urine. A positive finding for glucose on urinalysis indicates high blood sugar. The most appropriate action would be to perform a capillary artery glucose assessment. The client needs further evaluation for this abnormal result; therefore, documenting and continuing to monitor is not appropriate. Requesting a 24-hour urine test or reviewing the client’s dietary selections will not assist the nurse to make a clinical decision related to this abnormality.

4. Why is the combination drug trimethoprim-sulfamethoxazole (TMP-SMX) necessary?

• A. To broaden the antibacterial spectrum.
• B. To decrease bacterial resistance.
• C. To improve the taste.
• D. To minimize toxic effects.

Correct answer: B

Rationale: The correct answer is B: To decrease bacterial resistance. Trimethoprim-sulfamethoxazole (TMP-SMX) is a combination drug used to prevent bacterial resistance to sulfonamides. It works by targeting different steps in the bacterial metabolic pathway, making it harder for bacteria to develop resistance. Choice A is incorrect because the combination does not broaden the antibacterial spectrum; instead, it enhances effectiveness against specific bacteria. Choice C is incorrect as taste improvement is not the primary reason for combining these drugs. Choice D is incorrect because while combination therapy can sometimes help minimize toxic effects, the primary purpose in this case is to address bacterial resistance.

5. A client with renal insufficiency and a low red blood cell count asks, 'Is my anemia related to the renal insufficiency?' How should the nurse respond?

• A. Red blood cells produce erythropoietin, which increases blood flow to the kidneys.
• B. Your anemia and renal insufficiency are related to inadequate vitamin D and a loss of bone density.
• C. Erythropoietin is usually released from the kidneys and stimulates red blood cell production in the bone marrow.
• D. Kidney insufficiency inhibits active transportation of red blood cells throughout the blood.

Correct answer: C

Rationale: The correct answer is C. Erythropoietin is produced in the kidney and is released in response to decreased oxygen tension in the renal blood supply. Erythropoietin stimulates red blood cell production in the bone marrow. Anemia in renal insufficiency is often due to decreased erythropoietin production. Anemia and renal insufficiency are not manifestations of vitamin D deficiency as stated in choice B. Choice A is incorrect as erythropoietin does not increase blood flow to the kidneys. Choice D is incorrect because kidney insufficiency does not inhibit active transportation of red blood cells throughout the blood; rather, it affects erythropoietin production and subsequent red blood cell formation.

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