HESI RN
HESI Medical Surgical Practice Exam
1. Angiotensin-converting enzyme (ACE) inhibitors may be prescribed for the client with diabetes mellitus to reduce vascular changes and possibly prevent or delay the development of:
- A. Chronic obstructive pulmonary disease (COPD).
- B. Pancreatic cancer.
- C. Renal failure.
- D. Cerebrovascular accident.
Correct answer: C
Rationale: The correct answer is C: Renal failure. ACE inhibitors are commonly used in clients with diabetes mellitus to help reduce the progression of diabetic nephropathy by improving renal blood flow. This medication class can help prevent or delay the development of renal failure in these clients. Choices A, B, and D are incorrect because ACE inhibitors do not have a direct impact on preventing or delaying the development of chronic obstructive pulmonary disease, pancreatic cancer, or cerebrovascular accidents in clients with diabetes mellitus.
2. A client who underwent lobectomy 24 hours ago has not had any chest tube drainage for the past hour. What should the nurse do first?
- A. Contacts the physician
- B. Checks for kinks in the drainage system
- C. Checks the client’s blood pressure and heart rate
- D. Connects a new drainage system to the client’s chest tube
Correct answer: B
Rationale: When a chest tube is not draining, the nurse's initial action should be to check for kinks or clots in the chest drainage system. This step helps to ensure the patency of the system and allows for proper drainage. Checking the client's blood pressure and heart rate is important but not the priority when addressing a lack of chest tube drainage. Contacting the physician is warranted if signs of respiratory distress or mediastinal shift are observed after ruling out kinks or clots. Connecting a new drainage system is done when the fluid chamber is full, following a specific procedure to maintain a closed system and prevent complications.
3. A client with Diabetes Insipidus (DI) is being cared for by a nurse. Which data warrants the most immediate intervention by the nurse?
- A. Serum sodium of 185 mEq/L (185 mmol/L)
- B. Dry skin with poor skin turgor
- C. Apical rate of 110 beats per minute
- D. Polyuria and excessive thirst
Correct answer: A
Rationale: A serum sodium level of 185 mEq/L (185 mmol/L) is dangerously high and indicates severe dehydration, requiring immediate intervention to prevent neurological damage. The other options are not as critical as high serum sodium levels, which can lead to serious complications such as seizures, coma, and death if not promptly addressed. Dry skin with poor skin turgor and polyuria with excessive thirst are common findings in clients with Diabetes Insipidus and should be managed but do not pose an immediate threat to the client's life. An apical heart rate of 110 beats per minute may indicate tachycardia, which could be related to dehydration but is not as urgent as addressing the severe hypernatremia.
4. When providing care for an unconscious client who has seizures, which nursing intervention is most essential?
- A. Ensure oral suction is available.
- B. Maintain the client in a semi-Fowler's position.
- C. Provide frequent mouth care.
- D. Keep the room at a comfortable temperature.
Correct answer: A
Rationale: During seizures in an unconscious client, ensuring oral suction is available is crucial to managing secretions and preventing aspiration. This intervention helps maintain a clear airway and reduce the risk of complications. Maintaining the client in a semi-Fowler's position (Choice B) may be important for airway management but is not as critical as having oral suction ready. Providing frequent mouth care (Choice C) and keeping the room at a comfortable temperature (Choice D) are important aspects of overall care but are not as urgently needed as ensuring oral suction for managing secretions during seizures.
5. The client with type 1 diabetes mellitus is taught to take isophane insulin suspension NPH (Humulin N) at 5 PM each day. The client should be instructed that the greatest risk of hypoglycemia will occur at about what time?
- A. 11 AM, shortly before lunch.
- B. 1 PM, shortly after lunch.
- C. 6 PM, shortly after dinner.
- D. 1 AM, while sleeping.
Correct answer: D
Rationale: The correct answer is D, 1 AM, while sleeping. Isophane insulin suspension NPH (Humulin N) peaks around 6-8 hours after administration, which increases the risk of hypoglycemia during the night. Choice A, 11 AM, shortly before lunch, is incorrect because the peak effect of NPH insulin occurs much later. Choice B, 1 PM, shortly after lunch, is incorrect as it is too early for the peak effect of NPH insulin. Choice C, 6 PM, shortly after dinner, is also incorrect because the peak risk of hypoglycemia with NPH insulin occurs later in the night.
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