a nurse is watching as a nursing assistant measures the blood pressure bp of a hypertensive client which actions on the part of the assistant that wou
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Nursing Elites

HESI RN

HESI Medical Surgical Specialty Exam

1. A nursing assistant is measuring the blood pressure (BP) of a hypertensive client while a nurse observes. Which action on the part of the assistant would interfere with accurate measurement and prompt the nurse to intervene? Select all that apply.

Correct answer: C

Rationale: To ensure accurate blood pressure (BP) measurement, the cuff used should have a rubber bladder that encircles at least 80% of the limb being measured. This ensures proper compression and accurate readings. Choices A and B are correct practices as it is recommended to measure BP after the client has sat quietly for 5 minutes and to have the client sit with the arm bared and supported at heart level. Choice D is also a correct reason for intervention as the client should not have consumed caffeine or smoked tobacco within 30 minutes before BP measurement, as it can affect the accuracy of the reading.

2. When a young client being taught to use an inhaler for asthma symptoms states the intention to use the inhaler but plans to continue smoking cigarettes, what is the best initial action by the nurse?

Correct answer: B

Rationale: The best initial action by the nurse when a client expresses plans to use an inhaler for asthma symptoms but continue smoking cigarettes is to address denial. By explaining that denial of illness can interfere with the treatment regimen, the nurse educates the client about the impact of smoking on asthma treatment. This approach helps the client understand the importance of smoking cessation in managing asthma symptoms. Informing the healthcare provider (Choice A) may be necessary but is not the initial action in this scenario. Revising the plan of care (Choice C) should be considered after addressing the client's denial and educating them. Reviewing factors surrounding the client's beliefs about smoking cessation (Choice D) is relevant but not the best initial action when denial is identified.

3. The provider has ordered Kayexalate and sorbitol to be administered to a patient. The nurse caring for this patient would expect which serum electrolyte values prior to administration of this therapy?

Correct answer: C

Rationale: Severe hyperkalemia, with a potassium level of 6.9 mEq/L, requires aggressive treatment with Kayexalate and sorbitol to increase the body’s excretion of potassium. The normal range for serum potassium is 3.5 to 5.5 mEq/L, so patients with the other potassium levels would not be treated aggressively or would need potassium supplementation. Therefore, option C (Sodium 135 mEq/L and potassium 6.9 mEq/L) is the correct choice as it indicates severe hyperkalemia warranting the administration of Kayexalate and sorbitol. Options A, B, and D have either potassium levels within normal limits, which would not necessitate this aggressive treatment, or potassium levels that are lower than what would typically prompt the need for Kayexalate and sorbitol.

4. The client admitted with peripheral vascular disease (PVD) asks the nurse why her legs hurt when she walks. The nurse bases a response on the knowledge that the main characteristic of PVD is:

Correct answer: A

Rationale: The correct answer is A: 'Decreased blood flow.' In peripheral vascular disease (PVD), there is a narrowing or blockage of blood vessels, leading to reduced blood flow to the extremities. This decreased blood flow results in inadequate oxygen supply to the muscles, causing pain, especially during physical activity when oxygen demand increases. Choice B, 'Increased blood flow,' is incorrect because PVD is characterized by impaired blood circulation rather than increased flow. Choice C, 'Slow blood flow,' is not precise as PVD involves a more significant reduction in blood flow. Choice D, 'Thrombus formation,' is related to the formation of blood clots within vessels, which can be a complication of PVD but is not its main characteristic.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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