Nursing Elites

1. A client with type 1 diabetes mellitus has a blood glucose level of 620 mg/dL. After the nurse calls the physician to report the finding and monitors the client closely for:

• A. Metabolic acidosis
• B. Metabolic alkalosis
• C. Respiratory acidosis
• D. Respiratory alkalosis

Correct answer: A

Rationale: In the scenario described, a client with a blood glucose level of 620 mg/dL and type 1 diabetes mellitus is at risk of developing metabolic acidosis. In type 1 diabetes, the lack of sufficient circulating insulin leads to an increase in blood glucose levels. As the body cells utilize all available glucose, the breakdown of fats for energy results in the production of ketones, leading to metabolic acidosis. Metabolic alkalosis, respiratory acidosis, and respiratory alkalosis are not typically associated with uncontrolled type 1 diabetes. Metabolic alkalosis is more commonly linked to conditions such as vomiting or excessive diuretic use, while respiratory acidosis and respiratory alkalosis are related to respiratory system imbalances in carbon dioxide levels.

2. The healthcare provider is developing standards of care for a client with gastroesophageal reflux disease and wants to review current evidence for practice. Which one of the following resources will provide the most helpful information?

• A. A review in the Cochrane Library.
• B. A literature search in a database, such as the Cumulative Index to Nursing and Allied Health Literature (CINAHL).
• C. An online nursing textbook.
• D. The policy and procedure manual at the healthcare agency.

Correct answer: A

Rationale: The Cochrane Library provides systematic reviews of primary research in healthcare, making it a reliable resource for evidence-based practice. Choice B, a literature search in a database like CINAHL, may also be useful but does not guarantee the same level of systematic review and reliability as the Cochrane Library. Choice C, an online nursing textbook, may offer information but might not provide the most current or evidence-based practices. Choice D, the policy and procedure manual at the healthcare agency, is unlikely to offer the comprehensive evidence-based information needed for developing standards of care.

3. Which of the following medications is typically used to treat asthma?

• A. Aspirin
• B. Metformin
• C. Albuterol
• D. Lisinopril

Correct answer: C

Rationale: The correct answer is C, Albuterol. Albuterol is a bronchodilator commonly used to treat asthma by relaxing the muscles around the airways, helping to relieve symptoms such as coughing, wheezing, shortness of breath, and chest tightness. Aspirin (Choice A) is not typically used to treat asthma and can actually trigger asthma symptoms in some individuals. Metformin (Choice B) is a medication for managing type 2 diabetes and is not indicated for asthma treatment. Lisinopril (Choice D) is an angiotensin-converting enzyme (ACE) inhibitor primarily used to treat high blood pressure and heart failure, not asthma.

4. A client with autosomal dominant polycystic kidney disease (ADPKD) asks, “Will my children develop this disease?” How should the nurse respond?

• A. No genetic link is known, so your children are not at increased risk.
• B. Your sons will develop this disease because it has a sex-linked gene.
• C. Only if both you and your spouse are carriers of this disease.
• D. Each of your children has a 50% risk of having ADPKD.

Correct answer: D

Rationale: Children whose parent has the autosomal dominant form of PKD have a 50% chance of inheriting the gene that causes the disease. ADPKD is transmitted as an autosomal dominant trait and therefore is not gender-specific. Both parents do not need to have this disorder. Choice A is incorrect because ADPKD has a known genetic link and a definitive mode of inheritance. Choice B is incorrect as ADPKD is not sex-linked but autosomal dominant. Choice C is incorrect because ADPKD follows an autosomal dominant inheritance pattern and does not require both parents to be carriers for the child to inherit the disease.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

• A. Failing eyesight causing an unsafe environment.
• B. Renal osteodystrophy due to chronic renal failure.
• C. Osteoporosis due to hormonal changes.
• D. Cardiovascular changes leading to small strokes impairing mental acuity.

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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