Nursing Elites

1. A client with histoplasmosis has the following arterial blood gas (ABG) results: pH 7.30, PCO2 58 mm Hg, PO2 75 mm Hg, HCO3 27 mEq/L. Which of the following acid-base disturbances does the nurse recognize in these results?

• A. Metabolic acidosis
• B. Metabolic alkalosis
• C. Respiratory acidosis
• D. Respiratory alkalosis

Correct answer: A

Rationale: The client's ABG results show a low pH (acidosis) and an elevated PCO2, indicating respiratory acidosis. In respiratory acidosis, there is inadequate excretion of CO2, leading to increased PCO2 levels and a decrease in pH. Therefore, the correct answer is 'Metabolic acidosis'. Choices B, C, and D are incorrect. Metabolic alkalosis is characterized by elevated pH and bicarbonate levels. Respiratory acidosis involves low pH and high PCO2 levels, as seen in this case. Respiratory alkalosis is associated with high pH and low PCO2 levels.

2. A client with chronic obstructive pulmonary disease (COPD) who is beginning oxygen therapy asks the nurse why the flow rate cannot be increased to more than 2 L/min. The nurse responds that this would be harmful because it could:

• A. Be drying to nasal passages
• B. Decrease the client’s oxygen-based respiratory drive
• C. Increase the risk of pneumonia due to drier air passages
• D. Decrease the client’s carbon dioxide–based respiratory drive

Correct answer: B

Rationale: Increasing the oxygen flow rate beyond 2 L/min for a client with COPD can decrease the client's oxygen-based respiratory drive. In clients with COPD, the natural respiratory drive is based on the level of oxygen instead of carbon dioxide, as seen in healthy individuals. Increasing the oxygen level independently can suppress the drive to breathe, leading to respiratory failure. Choices A, C, and D are incorrect because drying of nasal passages, increased risk of pneumonia due to drier air passages, and decreasing the carbon dioxide-based respiratory drive are not the primary concerns associated with increasing the oxygen flow rate in a client with COPD.

3. A client with acute kidney injury (AKI) weighing 50kg and having a potassium level of 6.7mEq/L (6.7mmol/L) is admitted to the hospital. Which prescribed medication should the nurse administer first?

• A. Calcium acetate, one tablet by mouth
• B. Sodium polystyrene sulfonate, 15 grams by mouth
• C. Epoetin Alfa, recombinant, 2,500 units subcutaneously
• D. Sevelamer, one tablet by mouth

Correct answer: B

Rationale: In a client with acute kidney injury (AKI) and hyperkalemia, the priority intervention is to lower the potassium level swiftly. Sodium polystyrene sulfonate is a medication used to treat hyperkalemia by exchanging sodium ions for potassium ions in the intestines, reducing the overall potassium levels. Calcium acetate, epoetin alfa, and sevelamer are not indicated for the immediate reduction of potassium levels in hyperkalemia. Calcium acetate is used to control phosphate levels, epoetin alfa is a medication to treat anemia by stimulating red blood cell production, and sevelamer is a phosphate binder used in chronic kidney disease to reduce phosphate levels.

4. What is an expected outcome when a client is receiving an IV administration of furosemide?

• A. Increased blood pressure.
• B. Increased urine output.
• C. Decreased pain.
• D. Decreased premature ventricular contractions.

Correct answer: B

Rationale: The correct answer is B: Increased urine output. Furosemide is a loop diuretic that works by inhibiting the reabsorption of sodium and chloride in the ascending loop of Henle in the kidneys, leading to increased urine production. This diuretic effect helps to reduce fluid volume in the body, making it an expected outcome when a client is receiving furosemide. Choice A, increased blood pressure, is incorrect because furosemide typically causes a decrease in blood pressure due to its diuretic effect. Choice C, decreased pain, and choice D, decreased premature ventricular contractions, are unrelated to the pharmacological action of furosemide.

5. The client with type 1 diabetes mellitus is taught to take isophane insulin suspension NPH (Humulin N) at 5 PM each day. The client should be instructed that the greatest risk of hypoglycemia will occur at about what time?

• A. 11 AM, shortly before lunch.
• B. 1 PM, shortly after lunch.
• C. 6 PM, shortly after dinner.
• D. 1 AM, while sleeping.

Correct answer: D

Rationale: The correct answer is D, 1 AM, while sleeping. Isophane insulin suspension NPH (Humulin N) peaks around 6-8 hours after administration, which increases the risk of hypoglycemia during the night. Choice A, 11 AM, shortly before lunch, is incorrect because the peak effect of NPH insulin occurs much later. Choice B, 1 PM, shortly after lunch, is incorrect as it is too early for the peak effect of NPH insulin. Choice C, 6 PM, shortly after dinner, is also incorrect because the peak risk of hypoglycemia with NPH insulin occurs later in the night.

Similar Questions