Nursing Elites

1. A client was admitted for a myocardial infarction and cardiogenic shock 2 days ago. Which laboratory test result should a nurse expect to find?

• A. Blood urea nitrogen (BUN) of 52 mg/dL
• B. Creatinine of 2.3 mg/dL
• C. BUN of 10 mg/dL
• D. BUN/creatinine ratio of 8:1

Correct answer: A

Rationale: In cardiogenic shock, decreased renal perfusion leads to an elevated BUN. Choice A is correct. Creatinine remains normal in cardiogenic shock as it signifies kidney damage, which has not occurred in this case. A low BUN indicates overhydration, malnutrition, or liver damage, which are not typically seen in cardiogenic shock. A low BUN/creatinine ratio is associated with fluid volume excess or acute renal tubular acidosis, not specifically indicative of cardiogenic shock.

2. A client with early breast cancer receives the results of a breast biopsy and asks the nurse to explain the meaning of staging and the type of receptors found on the cancer cells. Which explanation should the nurse provide?

• A. Lymph node involvement is not significant.
• B. Small tumors are aggressive and indicate poor prognosis.
• C. The tumor's estrogen receptor guides treatment options.
• D. Stage I indicates metastasis.

Correct answer: C

Rationale: Treatment decisions and prediction of prognosis are related to the tumor's receptor status, such as estrogen and progesterone receptor status which commonly are well-differentiated, have a lower chance of recurrence, and are receptive to hormonal therapy. Tumor staging designates tumor size and spread of breast cancer cells into axillary lymph nodes, which is one of the most important prognostic factors in early-stage breast cancer.

3. When planning activities for a socialization group for older residents of a long-term facility, what information would be most useful for the nurse?

• A. The length of time each resident has resided at the facility.
• B. A brief description of each resident's family life.
• C. The age of each resident.
• D. The usual activity patterns of each resident.

Correct answer: D

Rationale: The most useful information for the nurse when planning activities for a socialization group for older residents of a long-term facility would be the usual activity patterns of each resident. An older person's level of activity is a determining factor in adjustment to aging, as described by the Activity Theory of Aging. By understanding the usual activity patterns of each resident, the nurse can tailor activities that cater to their interests and abilities, promoting social engagement and overall well-being. The other options, such as the length of time residing at the facility, a brief description of family life, or the age of each resident, may provide some insights but do not directly relate to planning activities that support adjustment to aging and socialization within the group.

4. The client admitted with peripheral vascular disease (PVD) asks the nurse why her legs hurt when she walks. The nurse bases a response on the knowledge that the main characteristic of PVD is:

• A. Decreased blood flow.
• B. Increased blood flow.
• C. Slow blood flow.
• D. Thrombus formation.

Correct answer: A

Rationale: The correct answer is A: 'Decreased blood flow.' In peripheral vascular disease (PVD), there is a narrowing or blockage of blood vessels, leading to reduced blood flow to the extremities. This decreased blood flow results in inadequate oxygen supply to the muscles, causing pain, especially during physical activity when oxygen demand increases. Choice B, 'Increased blood flow,' is incorrect because PVD is characterized by impaired blood circulation rather than increased flow. Choice C, 'Slow blood flow,' is not precise as PVD involves a more significant reduction in blood flow. Choice D, 'Thrombus formation,' is related to the formation of blood clots within vessels, which can be a complication of PVD but is not its main characteristic.

5. What most likely led to the 67-year-old woman who lives alone tripping on a rug in her home and fracturing her hip?

• A. Failing eyesight causing an unsafe environment.
• B. Renal osteodystrophy due to chronic renal failure.
• C. Osteoporosis due to hormonal changes.
• D. Cardiovascular changes leading to small strokes impairing mental acuity.

Correct answer: C

Rationale: The correct answer is C. Osteoporosis, caused by hormonal changes in later life, is the most likely predisposing factor for the fracture in the proximal end of her femur. Osteoporosis leads to reduced bone density, making bones more fragile and susceptible to fractures, especially in the elderly. Choices A, B, and D are less likely to directly lead to a hip fracture in this scenario. Failing eyesight (choice A) could contribute to the fall but is not the main predisposing factor for the fracture. Renal osteodystrophy (choice B) and cardiovascular changes (choice D) are less commonly associated with hip fractures compared to osteoporosis in elderly women.

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