Nursing Elites

1. The patient will begin taking penicillin G procaine (Wycillin). The nurse notes that the solution is milky in color. What action will the nurse take?

• A. Call the pharmacist and report the milky color.
• B. Add normal saline to dilute the medication.
• C. Call the physician and report the milky appearance.
• D. Administer the medication as ordered by the physician.

Correct answer: D

Rationale: The correct answer is to administer the medication as ordered by the physician. Penicillin G procaine (Wycillin) is known to have a milky appearance, which is normal. The milky color should not raise concerns for the nurse as it is an expected characteristic of this medication. Calling the pharmacist (choice A) or the physician (choice C) unnecessarily would delay the administration of the medication. Adding normal saline to dilute the medication (choice B) is not appropriate and could alter the medication's effectiveness. Therefore, the nurse should proceed with administering the medication as prescribed without any further action based on its milky appearance.

2. In a patient with liver cirrhosis, which of the following lab results would be expected?

• A. Increased bilirubin levels.
• B. Decreased albumin levels.
• C. Increased liver enzymes.
• D. Decreased platelet count.

Correct answer: A

Rationale: In a patient with liver cirrhosis, increased bilirubin levels would be expected. Liver cirrhosis leads to impaired liver function, causing a decrease in the liver's ability to process bilirubin, leading to its accumulation in the blood. This results in elevated bilirubin levels. Decreased albumin levels (choice B) may occur in liver cirrhosis due to impaired liver synthesis of proteins, but it is not as specific as increased bilirubin levels. Increased liver enzymes (choice C) can be seen in liver damage but are not as characteristic as elevated bilirubin levels. Decreased platelet count (choice D) can occur in liver cirrhosis due to hypersplenism, but it is not as specific as increased bilirubin levels in this context.

3. A client with polycystic kidney disease (PKD is being assessed by a nurse. Which assessment finding should prompt the nurse to immediately contact the healthcare provider?

• A. Flank pain
• B. Periorbital edema
• C. Bloody and cloudy urine
• D. Enlarged abdomen

Correct answer: B

Rationale: Periorbital edema would not typically be associated with polycystic kidney disease (PKD) and could indicate other underlying issues that require immediate attention. Flank pain and an enlarged abdomen are common findings in PKD due to kidney enlargement and displacement of other organs. Bloody or cloudy urine can result from cyst rupture or infection, which are expected in PKD. Therefore, periorbital edema is the most alarming finding in this scenario and warrants prompt notification of the healthcare provider.

4. After a myocardial infarction, why is the hospitalized client taught to move the legs while resting in bed?

• A. Prepare the client for ambulation.
• B. Promote urinary and intestinal elimination.
• C. Prevent thrombophlebitis and blood clot formation.
• D. Decrease the likelihood of pressure ulcer formation.

Correct answer: C

Rationale: The correct answer is C. Moving the legs helps prevent thrombophlebitis and blood clot formation by promoting venous return in clients on bed rest. This prevents stasis and clot formation in the lower extremities. Choices A, B, and D are incorrect because the primary goal of moving the legs is to prevent thrombophlebitis and blood clot formation, rather than preparing for ambulation, promoting elimination, or decreasing pressure ulcer formation. Ambulation preparation involves different exercises, urinary and intestinal elimination are not directly related to leg movements, and pressure ulcer prevention is more related to repositioning and skin care.

5. What is the most common cause of coronary artery disease?

• A. Atherosclerosis.
• B. Hyperlipidemia.
• C. Diabetes.
• D. Smoking.

Correct answer: A

Rationale: The correct answer is Atherosclerosis. It is the primary cause of coronary artery disease, as it involves the buildup of plaque in the arteries, restricting blood flow to the heart. Hyperlipidemia (choice B) contributes to atherosclerosis by increasing cholesterol levels in the blood but is not the direct cause of coronary artery disease. Diabetes (choice C) can accelerate atherosclerosis due to high blood sugar levels, but it is not the most common cause. Smoking (choice D) is a significant risk factor for developing coronary artery disease but is not the primary cause.

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