Nursing Elites

1. Why is glucose an important molecule in a cell?

• A. Extraction of energy
• B. Synthesis of protein
• C. Building of genetic material
• D. Formation of cell membranes

Correct answer: A

Rationale: Glucose is a crucial molecule in cells because it serves as the primary source of energy through cellular respiration. Choice B, the synthesis of protein, is incorrect because proteins are typically synthesized from amino acids, not glucose. Choice C, the building of genetic material, is incorrect because genetic material, such as DNA and RNA, is not directly built from glucose. Choice D, the formation of cell membranes, is also incorrect as cell membranes are primarily composed of lipids and proteins, not glucose.

2. Which of the following actions could be considered a breach of patient confidentiality?

• A. Discussing patient information with other healthcare providers in a private setting.
• B. Sharing patient information with family members without the patient's consent.
• C. Discussing patient information in public areas where others may overhear.
• D. Sharing patient information in a private, secure setting with other healthcare providers involved in the patient's care.

Correct answer: C

Rationale: Discussing patient information in public areas where others may overhear is considered a breach of patient confidentiality because it compromises the privacy and confidentiality of the patient's health information. Choices A and D are not breaches of confidentiality as discussing patient information with other healthcare providers in a private setting or in a private, secure setting with those involved in the patient's care is appropriate. Choice B is also incorrect as sharing patient information with family members without the patient's consent could potentially be a breach of privacy but is not the best answer in this context.

3. A client with type 1 diabetes mellitus presents with nausea, vomiting, and abdominal pain. The nurse suspects diabetic ketoacidosis (DKA). Which of the following lab findings would confirm this diagnosis?

• A. Serum glucose of 180 mg/dL
• B. Serum bicarbonate of 22 mEq/L
• C. Blood pH of 7.25
• D. Urine specific gravity of 1.020

Correct answer: C

Rationale: A blood pH of 7.25 is a critical finding in diabetic ketoacidosis (DKA) as it indicates metabolic acidosis, which is a hallmark of this condition. In DKA, there is an accumulation of ketones in the blood, leading to increased acidity. The serum glucose level is typically elevated in DKA, often exceeding 250 mg/dL. A serum bicarbonate level less than 18 mEq/L is usually seen in DKA due to the metabolic acidosis. Urine specific gravity is not a specific indicator for DKA and may vary depending on the individual's hydration status. Therefore, the correct lab finding that confirms DKA in this scenario is a blood pH of 7.25.

4. An incoherent female client with a history of hypothyroidism is brought to the emergency department by the rescue squad. Physical and laboratory findings reveal hypothermia, hypoventilation, respiratory acidosis, bradycardia, hypotension, and nonpitting edema of the face and pretibial area. Knowing that these findings suggest severe hypothyroidism, Nurse Libby prepares to take emergency action to prevent the potential complication of:

• A. Thyroid storm.
• B. Cretinism.
• C. Myxedema coma.
• D. Hashimoto's thyroiditis.

Correct answer: C

Rationale: The scenario described with hypothermia, hypoventilation, respiratory acidosis, bradycardia, hypotension, and nonpitting edema of the face and pretibial area is indicative of myxedema coma, a severe and life-threatening complication of hypothyroidism. Myxedema coma requires immediate emergency treatment to prevent further deterioration. Choice A, thyroid storm, is a complication of hyperthyroidism characterized by an increase in body temperature, heart rate, and blood pressure. Choice B, cretinism, refers to untreated congenital hypothyroidism leading to mental and physical growth retardation. Choice D, Hashimoto's thyroiditis, is an autoimmune condition leading to hypothyroidism but does not present with the acute, life-threatening symptoms described in the scenario.

5. A client with DM visits the health care clinic. The client's diabetes has been well controlled with glyburide (Diabeta), 5 mg PO daily, but recently the fasting blood glucose has been running 180-200 mg/dl. Which medication, if added to the client's regimen, may have contributed to the hyperglycemia?

• A. Atenolol (Tenormin)
• B. Prednisone (Deltasone)
• C. Phenelzine (Nardil)
• D. Allopurinol (Zyloprim)

Correct answer: B

Rationale: The correct answer is B. Prednisone is a corticosteroid that can cause hyperglycemia by increasing glucose production in the liver. Atenolol (Choice A) is a beta-blocker that typically does not affect blood glucose levels significantly. Phenelzine (Choice C) is a monoamine oxidase inhibitor used for depression and does not directly impact blood glucose levels. Allopurinol (Choice D) is a xanthine oxidase inhibitor used to manage gout and does not contribute to hyperglycemia.

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