ATI TEAS 7
TEAS 7 practice test science
1. Which of the following units is used to express concentration as a mass of solute per unit volume of solution?
- A. Molality (m)
- B. Molarity (M)
- C. Weight percent (%)
- D. Parts per million (ppm)
Correct answer: A
Rationale: Molality (m) is the unit used to express concentration as a mass of solute per unit volume of solution. It is calculated by dividing the mass of solute in grams by the mass of the solvent in kilograms. Molality is preferred over molarity when there are large temperature variations as it is temperature-independent, making it a more accurate measure of concentration. Molarity (B) is the unit used to express concentration as moles of solute per liter of solution, weight percent (C) is the mass of solute per 100 parts of the total mass of the solution, and parts per million (D) is used to express very small concentrations where 1 ppm is equivalent to 1 mg of solute per liter of solution.
2. Adipose tissue, also known as fat, serves multiple functions. Which of these is NOT a function of adipose tissue?
- A. Insulation
- B. Energy storage
- C. Hormone production
- D. Muscle movement
Correct answer: D
Rationale: Adipose tissue serves multiple functions in the body, including insulation to regulate body temperature, energy storage in the form of triglycerides, and hormone production such as leptin and adiponectin. Adipose tissue does not directly participate in muscle movement. Muscle movement is primarily carried out by skeletal muscle tissue, which is responsible for voluntary movements and locomotion. Therefore, the correct answer is D, as adipose tissue is not involved in muscle movement.
3. The chemical equation below is unbalanced. When it is properly balanced, how many molecules of carbon dioxide (CO2) are produced for each molecule of propane (C3H8) in the reaction? 3C3H8 + 5O2 → 3CO2 + 4H2O
- A. One Half.
- B. Two.
- C. Three.
- D. Five.
Correct answer: B
Rationale: The balanced chemical equation for the combustion of propane is: 3C3H8 + 5O2 → 3CO2 + 4H2O. This equation shows that for every 3 molecules of propane (C3H8) consumed, 3 molecules of carbon dioxide (CO2) are produced. Therefore, when properly balanced, 3CO2 are produced for each molecule of propane used. Thus, the correct answer is B: Two. Choices A, C, and D are incorrect because they do not reflect the correct stoichiometry as determined by the balanced equation.
4. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?
- A. 31.25 mL
- B. 32 mL
- C. 30 mL
- D. 31.3 mL
Correct answer: B
Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.
5. From which type of tissue is the myelin sheath derived, a fatty substance that insulates nerve fibers?
- A. Epithelial tissue
- B. Muscle tissue
- C. Nervous tissue (glial cells)
- D. Connective tissue
Correct answer: C
Rationale: The myelin sheath, a fatty substance that insulates nerve fibers, is derived from nervous tissue, specifically glial cells. Glial cells, including oligodendrocytes in the central nervous system and Schwann cells in the peripheral nervous system, are responsible for producing the myelin sheath that surrounds and insulates nerve fibers, aiding in the conduction of nerve impulses. Epithelial tissue (Choice A), Muscle tissue (Choice B), and Connective tissue (Choice D) are not responsible for producing the myelin sheath; instead, nervous tissue (glial cells) plays this crucial role.
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