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Nursing Elites

ATI TEAS 7

ATI TEAS Science

1. Which of the following lists of joint types is in the correct order for increasing amounts of permitted motion (least mobile to most mobile)?

Correct answer: A

Rationale: The correct order of joint types, from least mobile to most mobile, is hinge, condyloid, saddle. A hinge joint allows movement in one plane (like a door hinge), a condyloid joint allows movement in two planes but not rotation (like the wrist), and a saddle joint allows movement in multiple directions (like the thumb). Choice A, 'Hinge, condyloid, saddle,' is the correct sequence as it accurately represents the order of increasing permitted motion in joints. Choices B, C, and D are incorrect because they do not follow the correct order of joint types from least mobile to most mobile as required by the question.

2. Which of the following correctly lists the four properties that all types of muscle tissue share?

Correct answer: A

Rationale: The correct answer is A: 'Contractile, excitable, elastic, extensible.' All types of muscle tissue share these four properties. Muscle tissue can contract, respond to stimuli, stretch and return to its original shape (elastic), and extend or stretch (extensible). Choice B is incorrect because not all muscle tissues are voluntary (some are involuntary). Choice C is incorrect because not all muscle tissues are voluntary. Choice D is incorrect because not all muscle tissues are voluntary and lack the elastic property.

3. What is the molarity of a solution made by dissolving 4.0 grams of NaCl into enough water to make 120 mL of solution? The atomic mass of Na is 23.0 g/mol, and Cl is 35.5 g/mol.

Correct answer: B

Rationale: To find the molarity, first calculate the moles of NaCl. Moles of NaCl = 4.0 g / (23.0 g/mol + 35.5 g/mol) = 0.068 mol. Next, use the formula for molarity: Molarity = moles of solute / liters of solution. Molarity = 0.068 mol / 0.120 L = 0.57 M. Therefore, the molarity of the solution is 0.57 M. Choice A, 0.34 M, is incorrect as it does not match the calculated molarity. Choice C, 0.034 M, is incorrect as it is a decimal point off from the correct molarity. Choice D, 0.057 M, is incorrect as it does not match the calculated molarity of 0.57 M.

4. Blood type is a trait determined by multiple alleles, with IA and IB being co-dominant: IA codes for A blood and IB codes for B blood, while i codes for O blood and is recessive to both. If an A heterozygote individual and an O individual have a child, what is the probability that the child will have A blood?

Correct answer: B

Rationale: If an A heterozygote (IAi) and an O individual (ii) have a child, there is a 50% chance the child will inherit the IA allele and have A blood. The A heterozygote can pass on either the IA or i allele, while the O individual can only pass on the i allele. Therefore, the possible genotypes for the child are IAi (A blood) or ii (O blood), resulting in a 50% chance of the child having A blood. Choice A (25%) is incorrect as it does not take into account the possibility of inheriting the IA allele. Choice C (75%) and Choice D (100%) are incorrect as they overestimate the probability of the child having A blood.

5. Which of the following are the reproductive cells produced by meiosis?

Correct answer: D

Rationale: The correct answer is D. Gametes are the reproductive cells produced by meiosis. Meiosis is the cell division process that results in the formation of gametes, which are sperm cells in males and egg cells in females. Genes (A), alleles (B), and chromatids (C) are not the reproductive cells produced by meiosis. Genes are units of heredity, alleles are different forms of a gene, and chromatids are duplicated chromosomes involved in cell division.

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