ATI TEAS 7
TEAS Practice Test Math
1. A circle has an area of 121π in². Which of the following is the circumference of the circle in terms of pi (π)?
- A. 11π in
- B. 22π in
- C. 44π in
- D. 5.5π in
Correct answer: B
Rationale: To find the circumference of the circle, we first need to determine the radius. Given that the area of the circle is 121π in², we use the formula for the area of a circle (A = πr²) to find the radius squared. So, r² = 121, which means the radius (r) is 11 in. The circumference of a circle is calculated using the formula 2πr. Substituting the radius value of 11 in, we get 2π(11) = 22π in. Therefore, the correct answer is 22π in. Choice A (11π in), Choice C (44π in), and Choice D (5.5π in) are incorrect because they do not correctly calculate the circumference based on the given area of the circle.
2. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?
- A. 81 mg
- B. 270 mg
- C. 300 mg
- D. 351 mg
Correct answer: D
Rationale: To calculate a 30% increase from the current dosage of 270 mg, first find 30% of 270, which is 81 mg. Add this 81 mg increase to the original dosage of 270 mg to get the new dosage, which is 351 mg (270 mg + 81 mg = 351 mg). Therefore, the correct answer is 351 mg. Choice A (81 mg) is incorrect because this value represents only the calculated 30% increase, not the total dosage after the increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is close to the correct answer but does not consider the precise 30% increase calculation, leading to an incorrect total dosage.
3. Elevation above sea level and temperature are negatively correlated variables. Which of the following statements describes the relationship between the variables?
- A. As elevation decreases, temperature remains the same
- B. As elevation decreases, temperature decreases
- C. As elevation increases, temperature decreases
- D. As elevation increases, temperature increases
Correct answer: C
Rationale: The correct answer is C: 'As elevation increases, temperature decreases.' In a negative correlation, the variables move in opposite directions. As elevation rises, temperature tends to decrease. Choice A is incorrect because a negative correlation implies that as one variable increases, the other decreases. Choices B and D are incorrect because they suggest that temperature either remains the same or increases as elevation decreases or increases, which is inconsistent with a negative correlation.
4. A soccer field is rectangular in shape and is 100 meters long and 75 meters wide. The hectare is a metric unit of area often used to measure larger areas. Given that 1 hectare = 10,000 square meters, which of the following represents the soccer field’s area in hectares?
- A. 0.75 hectares
- B. 7.5 hectares
- C. 7,500 hectares
- D. 75,000,000 hectares
Correct answer: A
Rationale: To find the area of the soccer field, multiply its length by its width: 100 meters × 75 meters = 7500 square meters. To convert this to hectares, divide by 10,000 (since 1 hectare = 10,000 square meters), resulting in 0.75 hectares. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not correctly convert the area to hectares. B and C are off by a factor of 10, while D is off by a factor of 10,000.
5. A recipe calls for 5.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?
- A. 10.2 mL
- B. 12 mL
- C. 7.43 mL
- D. 27 mL
Correct answer: D
Rationale: To convert the amount of vanilla from teaspoons to milliliters, we multiply the number of teaspoons by the conversion factor of 4.93 mL/teaspoon. 5.5 teaspoons * 4.93 mL/teaspoon = 27.115 mL, which rounds to 27 mL. Therefore, the correct amount of vanilla in mL is 27 mL. Choice A (10.2 mL), Choice B (12 mL), and Choice C (7.43 mL) are incorrect as they do not correctly convert the given amount of teaspoons to milliliters based on the provided conversion factor.
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