Nursing Elites

1. What is the solution to 4 x 7 + (25 – 21)²?

• A. 512
• B. 36
• C. 44
• D. 22

Correct answer: C

Rationale: To find the solution, first solve the expression inside the parentheses: 25 - 21 = 4. Then, square the result from the parentheses: 4² = 16. Next, perform the multiplication: 4 x 7 = 28. Finally, add the results: 28 + 16 = 44. Therefore, the correct answer is 44. Choice A (512), Choice B (36), and Choice D (22) are incorrect as they do not follow the correct order of operations for solving the given mathematical expression.

2. Given the double bar graph shown below, which of the following statements is true?

• A. Group A is negatively skewed, while Group B is approximately normal.
• B. Group A is positively skewed, while Group B is approximately normal.
• C. Group A is approximately normal, while Group B is negatively skewed.
• D. Group A is approximately normal, while Group B is positively skewed.

Correct answer: B

Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.

3. A recipe calls for 0.375 cups of sugar, but you only want to make 0.625 of the recipe. How much sugar should you use?

• A. 1.125 cups
• B. 1.111 cups
• C. 0.6 cups
• D. 2.4 cups

Correct answer: C

Rationale: To find out how much sugar should be used when making 0.625 of the recipe, you need to multiply 0.375 (amount required for the full recipe) by 0.625 (proportion of the recipe you want to make). 0.375 * 0.625 = 0.234375. Therefore, you should use 0.234375 cups of sugar, which is equivalent to 0.6 cups. This is the correct answer. Choices A, B, and D are incorrect because they do not correctly calculate the adjusted amount of sugar needed based on the proportion of the recipe being made.

4. Which of the following statements is true?

• A. The mean is less than the median
• B. The mode is greater than the median
• C. The mode is less than the mean, median, and range
• D. The mode is equal to the range

Correct answer: A

Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.

5. As part of a study, a set of patients will be divided into three groups: 1/2 of the patients will be in Group Alpha, 1/3 of the patients will be in Group Beta, and 1/6 of the patients will be in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.

• A. Group Alpha, Group Beta, Group Gamma
• B. Group Alpha, Group Gamma, Group Beta
• C. Group Gamma, Group Alpha, Group Beta
• D. Group Gamma, Group Beta, Group Alpha

Correct answer: C

Rationale: The correct order from smallest to largest number of patients in each group is Group Gamma (1/6), Group Alpha (1/2), and Group Beta (1/3). Group Gamma has the smallest fraction of patients, followed by Group Alpha and then Group Beta. Therefore, choice C, 'Group Gamma, Group Alpha, Group Beta,' is the correct answer. Choices A, B, and D are incorrect because they do not follow the correct order based on the fractions of patients assigned to each group.

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