Nursing Elites

1. What is the mode of the numbers in the distribution shown in the table?

• A. 1
• B. 2
• C. 3
• D. 4

Correct answer: A

Rationale: The mode of a set of numbers is the value that appears most frequently. In the distribution shown in the table, the number '1' occurs more times than any other number, making it the mode. Choices B, C, and D are incorrect because they do not represent the number that occurs most frequently in the dataset.

2. The graph below represents the amount of rainfall in a particular state by month. What is the total rainfall for the months May, June, and July?

• A. 9.0 inches
• B. 8.4 inches
• C. 7.5 inches
• D. 10.5 inches

Correct answer: A

Rationale: To calculate the total rainfall for May, June, and July, we add the rainfall amounts for each month: 3.2 inches (May) + 2.5 inches (June) + 3.3 inches (July) = 9.0 inches. Therefore, the correct answer is A. Choice B (8.4 inches) is incorrect as it does not account for the correct sum of rainfall for the specified months. Choice C (7.5 inches) is incorrect as it does not include the accurate total rainfall for May, June, and July. Choice D (10.5 inches) is incorrect as it provides a total that exceeds the actual combined rainfall for the given months.

3. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?

• A. Histogram
• B. Pie chart
• C. Bar graph
• D. Scatter plot

Correct answer: A

Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.

4. Arrange the following fractions from least to greatest: 2/3, 1/2, 5/8, 7/9.

• A. 7/9, 5/8, 2/3, 1/2
• B. 1/2, 2/3, 5/8, 7/9
• C. 1/2, 5/8, 2/3, 7/9
• D. 7/9, 2/3, 5/8, 1/2

Correct answer: C

Rationale: To compare the fractions, it is beneficial to convert them to decimals or find a common denominator. When converted to decimals: 1/2 = 0.50, 5/8 = 0.625, 2/3 ≈ 0.666, and 7/9 ≈ 0.778. Therefore, the correct order from least to greatest is 1/2, 5/8, 2/3, 7/9. Choice A is incorrect because it places 7/9 first, which is the greatest fraction. Choice B is incorrect as it incorrectly lists the fractions. Choice D is incorrect as it starts with 7/9, which is the largest fraction instead of the smallest.

5. During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?

• A. 15 shifts
• B. 14 shifts
• C. 16 shifts
• D. 17 shifts

Correct answer: B

Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).

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