ATI TEAS 7
Practice Math TEAS TEST
1. What is the area of a square that measures 3.1m on each side?
- A. 12.4m²
- B. 9.61m²
- C. 6.2m²
- D. 9.1m²
Correct answer: B
Rationale: To find the area of a square, you square the length of one side. In this case, the side length is 3.1m. So, Area = side² = 3.1m × 3.1m = 9.61m². Therefore, the correct answer is 9.61m². Choice A (12.4m²) is incorrect as it is the result of multiplying 3.1m by 4 instead of squaring it. Choice C (6.2m²) is incorrect as it is half of the correct answer. Choice D (9.1m²) is incorrect as it is the result of squaring the wrong value (3.1²).
2. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8
- A. (1.8, 3.6) and (-1.8, -3.6)
- B. (1.8, -3.6) and (-1.8, 3.6)
- C. (1.3, 2.6) and (-1.3, -2.6)
- D. (-1.3, 2.6) and (1.3, -2.6)
Correct answer: B
Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.
3. Over several years, a real estate agent sold houses, with one year having an outlier where she sold 11 houses. Which of the following measures will most accurately reflect the number of houses she sold per year?
- A. mean
- B. median
- C. mode
- D. range
Correct answer: B
Rationale: The outlier of 11 would skew the data if the mean or range were used. The median, however, is not affected by outliers and is the most appropriate measure for reflecting the number of houses she sold per year. In this scenario, the data set does not have a mode as each value occurs only once, making mode not the most appropriate choice.
4. During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?
- A. 15 shifts
- B. 14 shifts
- C. 16 shifts
- D. 17 shifts
Correct answer: B
Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).
5. Express as an improper fraction: 8 3/7
- A. 11/7
- B. 21/8
- C. 5/3
- D. 59/7
Correct answer: D
Rationale: To convert the mixed number 8 3/7 to an improper fraction, multiply the whole number (8) by the denominator (7) and add the numerator (3) to get the numerator of the improper fraction. This gives us (8*7 + 3) / 7 = 59/7. Therefore, the correct answer is 59/7. Choice A (11/7), choice B (21/8), and choice C (5/3) are incorrect because they do not correctly convert the mixed number to an improper fraction.
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