ATI TEAS 7
TEAS Practice Math Test
1. Dr. Lee observed that 30% of all his patients developed an infection after taking a certain antibiotic. He further noticed that 5% of that 30% required hospitalization to recover from the infection. What percentage of Dr. Lee's patients were hospitalized after taking the antibiotic?
- A. 1.50%
- B. 5%
- C. 15%
- D. 30%
Correct answer: A
Rationale: To find the percentage of Dr. Lee's patients hospitalized after taking the antibiotic, we need to calculate 30% of 5%. First, convert 30% and 5% to decimals: 30% = 0.30 and 5% = 0.05. Multiply 0.30 by 0.05 to get 0.015. To convert 0.015 to a percentage, multiply by 100, resulting in 1.5%. Therefore, only 1.50% of Dr. Lee's patients were hospitalized after taking the antibiotic. Choice A is correct. Choice B (5%) is incorrect as it represents the percentage of patients who developed an infection and not those hospitalized. Choices C (15%) and D (30%) are also incorrect percentages as they do not accurately reflect the proportion of hospitalized patients in this scenario.
2. Four people split a bill. The first person pays 1/5, the second person pays 1/3, and the third person pays 1/12. What fraction of the bill does the fourth person pay?
- A. 1/4
- B. 13/60
- C. 47/60
- D. 1/4
Correct answer: C
Rationale: To find the fourth person's share, subtract the fractions paid by the first three people from the total bill (1). The first person pays 1/5, the second person pays 1/3, and the third person pays 1/12. Adding these fractions gives 7/15. Subtracting this from 1 gives the fourth person's share as 8/15, which simplifies to 4/5. Therefore, the fourth person pays 4/5 of the bill. Option A (1/4) is incorrect because it does not consider the fractions paid by the first three people. Option B (13/60) is incorrect as it is not the remainder after subtracting the first three fractions from 1. Option D (1/4) is a duplicate of Option A and is also incorrect.
3. The force applied is directly proportional to the stretch of a coil. If a force of 132 Newtons stretches a coil 0.07 meters, what force would be needed to stretch a coil 0.1 meter? Round your answer to the nearest tenth.
- A. 92.4 Newtons
- B. 1885.7 Newtons
- C. 188.6 Newtons
- D. 136.0 Newtons
Correct answer: C
Rationale: To find the force needed to stretch the coil 0.1 meters, we can set up a proportion based on the given information. The initial force and stretch are in direct proportion, so we can use this relationship to determine the unknown force. (132 N / 0.07 m) = X / 0.1 m. Cross-multiplying, we get 132 N * 0.1 m / 0.07 m = 188.57 N, which rounds to 188.6 N. Therefore, the correct answer is 188.6 Newtons. Choice A is incorrect as it does not match the calculated answer. Choice B is significantly higher and does not align with the proportional relationship. Choice D is close but does not account for the correct rounding as specified in the question.
4. A person drives 300 miles at 60 mph, then another 200 miles at 80 mph, with a 30-minute break. How long does the trip take?
- A. 5.5 hours
- B. 7 hours
- C. 6 hours
- D. 4.5 hours
Correct answer: C
Rationale: To find the total time, we calculate the time taken for each segment: 300 miles at 60 mph = 300 miles ÷ 60 mph = 5 hours; 200 miles at 80 mph = 200 miles ÷ 80 mph = 2.5 hours. Adding these gives 5 hours + 2.5 hours = 7.5 hours. Converting the 30-minute break to hours (30 minutes ÷ 60 = 0.5 hours), the total time taken is 7.5 hours + 0.5 hours = 8 hours. Therefore, the correct answer is not among the given choices. The rationale provided in the original question is incorrect as it does not account for the break time and has a calculation error in adding the individual times.
5. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?
- A. $1.75
- B. $2.00
- C. $2.25
- D. $2.50
Correct answer: C
Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.
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