the owner of a newspaper has noticed that print subscriptions have gone down 40 while online subscriptions have gone up 60 print subscriptions once ac
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ATI TEAS 7

TEAS Exam Math Practice

1. The owner of a newspaper has noticed that print subscriptions have gone down 40% while online subscriptions have gone up 60%. Print subscriptions once accounted for 70% of the newspaper’s business, and online subscriptions accounted for 25%. What is the overall percentage growth or decline in business?

Correct answer: A

Rationale: To calculate the decline in business, start with the 40% decline in the 70% share of print subscriptions: 40% of 70% = 0.40 × 0.70 = 0.28 = 28% decline. Next, calculate the growth from the 60% increase in the 25% share of online subscriptions: 60% of 25% = 0.60 × 0.25 = 0.15 = 15% growth. To find the overall change, sum the decline and growth percentages: 28% decline + 15% growth = -0.28 + 0.15 = -0.13 = 13% decline. Therefore, the overall percentage change in the newspaper's business is a 13% decline. Option A is the correct answer. Option B is incorrect because it doesn't consider the correct calculations for both the decline and growth. Option C is incorrect as it misinterprets the net change in business. Option D is incorrect as it miscalculates the overall percentage growth or decline.

2. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

3. Arrange the following fractions from least to greatest: 2/3, 1/2, 5/8, 7/9.

Correct answer: C

Rationale: To compare the fractions, it is beneficial to convert them to decimals or find a common denominator. When converted to decimals: 1/2 = 0.50, 5/8 = 0.625, 2/3 ≈ 0.666, and 7/9 ≈ 0.778. Therefore, the correct order from least to greatest is 1/2, 5/8, 2/3, 7/9. Choice A is incorrect because it places 7/9 first, which is the greatest fraction. Choice B is incorrect as it incorrectly lists the fractions. Choice D is incorrect as it starts with 7/9, which is the largest fraction instead of the smallest.

4. Apply the polynomial identity to rewrite (a + b)².

Correct answer: C

Rationale: When you see something like (a + b)², it means you're multiplying (a + b) by itself: (a + b)² = (a + b) × (a + b) To expand this, we use the distributive property (which says you multiply each term in the first bracket by each term in the second bracket): Multiply the first term in the first bracket (a) by both terms in the second bracket: a × a = a² a × b = ab Multiply the second term in the first bracket (b) by both terms in the second bracket: b × a = ab b × b = b² Now, add up all the results from the multiplication: a² + ab + ab + b² Since ab + ab is the same as 2ab, we can simplify it to: a² + 2ab + b² So, (a + b)² = a² + 2ab + b². This is known as a basic polynomial identity, and it shows that when you square a binomial (a two-term expression like a + b), you get three terms: the square of the first term (a²), twice the product of the two terms (2ab), and the square of the second term (b²). Therefore, the correct answer is C (a² + 2ab + b²)

5. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?

Correct answer: C

Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.

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