the owner of a newspaper has noticed that print subscriptions have gone down 40 while online subscriptions have gone up 60 print subscriptions once ac
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ATI TEAS 7

TEAS Exam Math Practice

1. The owner of a newspaper has noticed that print subscriptions have gone down 40% while online subscriptions have gone up 60%. Print subscriptions once accounted for 70% of the newspaper’s business, and online subscriptions accounted for 25%. What is the overall percentage growth or decline in business?

Correct answer: A

Rationale: To calculate the decline in business, start with the 40% decline in the 70% share of print subscriptions: 40% of 70% = 0.40 × 0.70 = 0.28 = 28% decline. Next, calculate the growth from the 60% increase in the 25% share of online subscriptions: 60% of 25% = 0.60 × 0.25 = 0.15 = 15% growth. To find the overall change, sum the decline and growth percentages: 28% decline + 15% growth = -0.28 + 0.15 = -0.13 = 13% decline. Therefore, the overall percentage change in the newspaper's business is a 13% decline. Option A is the correct answer. Option B is incorrect because it doesn't consider the correct calculations for both the decline and growth. Option C is incorrect as it misinterprets the net change in business. Option D is incorrect as it miscalculates the overall percentage growth or decline.

2. A consumer makes a $400 down payment on a television that costs $1,570. Which of the following is the number of months it will take to pay off the television with monthly payments of $100?

Correct answer: A

Rationale: After the $400 down payment, the remaining balance is $1,170. With monthly payments of $100, it will take 12 months to pay off the remaining balance. Therefore, the correct answer is 12 months. Choice B (16) is incorrect as it exceeds the required timeframe. Choice C (15) is incorrect as it is close but still one month over the correct timeframe. Choice D (11) is incorrect as it underestimates the time needed to pay off the remaining balance.

3. Which of the following lists is in order from least to greatest? 2−1 , −(4/3), (−1)3 , (2/5)

Correct answer: D

Rationale: To determine the correct order from least to greatest, start by simplifying the expressions. 2^(-1) = 1/2 and (-1)^3 = -1. Now, comparing the values, (-4/3) is the most negative, followed by -1, then (2/5), and finally 1/2. Therefore, the correct order is (-4/3), (-1)^3, (2/5), 2^(-1), making choice D the correct answer. Choices A, B, and C are incorrect because they do not follow the correct order from least to greatest as determined by comparing the values of the expressions after simplification.

4. The force applied is directly proportional to the stretch of a coil. If a force of 132 Newtons stretches a coil 0.07 meters, what force would be needed to stretch a coil 0.1 meter? Round your answer to the nearest tenth.

Correct answer: C

Rationale: To find the force needed to stretch the coil 0.1 meters, we can set up a proportion based on the given information. The initial force and stretch are in direct proportion, so we can use this relationship to determine the unknown force. (132 N / 0.07 m) = X / 0.1 m. Cross-multiplying, we get 132 N * 0.1 m / 0.07 m = 188.57 N, which rounds to 188.6 N. Therefore, the correct answer is 188.6 Newtons. Choice A is incorrect as it does not match the calculated answer. Choice B is significantly higher and does not align with the proportional relationship. Choice D is close but does not account for the correct rounding as specified in the question.

5. Order the groups from largest to smallest, according to the number of doctors in each group.

Correct answer: B

Rationale: The correct order from largest to smallest number of doctors in each group is Group Z (20 doctors), Group Y (15 doctors), and Group X (10 doctors). Therefore, the correct order is Group Z, Group Y, and Group X, which matches option B. Option B is correct because it correctly reflects the descending order of the number of doctors in each group. Options A, C, and D are incorrect as they do not follow the correct order of the number of doctors in each group.

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