Nursing Elites

1. A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?

• A. $2,240
• B. $2,800
• C. $3,360
• D. $4,480

Correct answer: C

Rationale: The field is a hexagon with six equal sides, each 320 feet long. To find the total cost of fencing material needed, multiply the cost per foot ($75) by the total perimeter of the field (6 sides x 320 feet). Therefore, the total cost will be $75 x 6 x 320 = $3,360. Thus, the farmer will need to spend $3,360 on fencing material. Choice A, $2,240, is incorrect as it does not account for the total perimeter of the field. Choice B, $2,800, is incorrect as it underestimates the total cost by not considering all sides of the hexagon. Choice D, $4,480, is incorrect as it overestimates the total cost by multiplying incorrectly or considering extra sides.

2. A study was conducted where patients were divided into three groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Which group is the smallest?

• A. Group Alpha
• B. Group Beta
• C. Group Gamma
• D. Group Gamma

Correct answer: C

Rationale: The smallest group is Group Gamma, which had 1/6 of the total number of patients. To determine the smallest group, compare the fractions representing the portions of patients in each group. 1/6 is smaller than 1/3 and 1/2, making Group Gamma the smallest. Group Alpha and Group Beta have larger fractions of patients, making them larger groups compared to Group Gamma.

3. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

4. If a product's original price is $80 and it is discounted by 20%, what is the final price?

• A. 64
• B. 60
• C. 70
• D. 66

Correct answer: A

Rationale: To find the discounted price, you first calculate 20% of the original price: 20% of $80 is $16. Subtracting this discount amount from the original price gives the final price: $80 - $16 = $64. Therefore, the final price after a 20% discount on a product originally priced at $80 is $64. Choice B, $60, is incorrect because it does not account for the correct discount amount. Choice C, $70, is incorrect as it does not reflect the reduction due to the 20% discount. Choice D, $66, is incorrect as it miscalculates the discounted price.

5. During week 1, Nurse Cameron works 5 shifts. During week 2, she worked twice as many shifts as she did in week 1. In week 3, she added 4 shifts to the number of shifts worked in week 2. Which equation describes the number of shifts Nurse Cameron worked in week 3?

• A. Shifts = (2)(5) + 4
• B. Shifts = (4)(5) + 2
• C. Shifts = 5 + 2 + 4
• D. Shifts = (5)(2)(4)

Correct answer: A

Rationale: During week 1, Nurse Cameron worked 5 shifts. In week 2, she worked twice as many shifts as in week 1, which is 10 shifts. In week 3, she added 4 shifts to the number of shifts worked in week 2. Therefore, the total shifts in week 3 can be calculated as (2)(5) + 4 = 10 + 4 = 14 shifts. Choice A correctly represents this calculation. Choices B, C, and D are incorrect because they do not accurately reflect the given scenario and the steps needed to find the total shifts in week 3.

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