Nursing Elites

1. A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?

• A. $2,240
• B. $2,800
• C. $3,360
• D. $4,480

Correct answer: C

Rationale: The field is a hexagon with six equal sides, each 320 feet long. To find the total cost of fencing material needed, multiply the cost per foot ($75) by the total perimeter of the field (6 sides x 320 feet). Therefore, the total cost will be $75 x 6 x 320 = $3,360. Thus, the farmer will need to spend $3,360 on fencing material. Choice A, $2,240, is incorrect as it does not account for the total perimeter of the field. Choice B, $2,800, is incorrect as it underestimates the total cost by not considering all sides of the hexagon. Choice D, $4,480, is incorrect as it overestimates the total cost by multiplying incorrectly or considering extra sides.

2. Express 3 5/7 as an improper fraction.

• A. 26/7
• B. 21/7
• C. 22/7
• D. 26/5

Correct answer: A

Rationale: To convert a mixed number to an improper fraction, multiply the whole number by the denominator of the fraction, then add the numerator. In this case, 3 * 7 + 5 = 21 + 5 = 26. So, 3 5/7 as an improper fraction is 26/7. Choice B (21/7) is incorrect because it represents the original fraction 3 5/7. Choice C (22/7) is incorrect and represents a different fraction. Choice D (26/5) is incorrect and does not reflect the proper conversion of the mixed number to an improper fraction.

3. When rounding 2678 to the nearest thousandth, which place value would be used to decide whether to round up or round down?

• A. Ten-thousandth
• B. Thousandth
• C. Hundredth
• D. Thousand

Correct answer: B

Rationale: When rounding 2678 to the nearest thousandth, you would look at the digit in the thousandth place, which is 7. To decide whether to round up or down, you consider the digit to the immediate right of the place you are rounding to. Since 7 is equal to or greater than 5, you round up. Choice A, ten-thousandth, is incorrect as we are rounding to the thousandth place. Choice C, hundredth, is not relevant as we are not rounding to that place value. Choice D, thousand, is incorrect as it is the original number being rounded, not the place value used for rounding.

4. Sally wants to buy a used truck for her delivery business. Truck A is priced at $450 and gets 25 miles per gallon. Truck B costs $650 and gets 35 miles per gallon. If gasoline costs $4 per gallon, how many miles must Sally drive to make truck B the better buy?

• A. 500
• B. 7500
• C. 1750
• D. 4375

Correct answer: D

Rationale: To determine the breakeven point where Truck B becomes the better buy, we need to compare the total costs for both trucks. For Truck A: Total cost = $450 + (miles / 25) * $4. For Truck B: Total cost = $650 + (miles / 35) * $4. To find the point where Truck B is the better buy, set the two total cost equations equal to each other and solve for miles. By solving this equation, we find that Sally must drive 4375 miles for Truck B to be the better buy. Choice A (500) is too low, Choice B (7500) is too high, and Choice C (1750) does not represent the breakeven point where Truck B becomes more cost-effective.

5. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

• A. (1.8, 3.6) and (-1.8, -3.6)
• B. (1.8, -3.6) and (-1.8, 3.6)
• C. (1.3, 2.6) and (-1.3, -2.6)
• D. (-1.3, 2.6) and (1.3, -2.6)

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

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