the area of a circle is 18 square inches find the circumference of the circle to the nearest tenth of an inch use 314 for
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ATI TEAS 7

TEAS Test Math Questions

1. Half of a circular garden with a radius of 11.5 feet needs weeding. Find the area in square feet that needs weeding. Round to the nearest hundredth. Use 3.14 for π.

Correct answer: B

Rationale: The formula for the area of a full circle is calculated as Area = π × (radius²). When finding the area of half a circle, we multiply by 0.5. Thus, the formula becomes Area = 0.5 × π × (radius²). Given that the radius of the circular garden is 11.5 feet, the calculation using π = 3.14 is as follows: Area = 0.5 × 3.14 × (11.5²) = 0.5 × 3.14 × 132.25 = 0.5 × 415.27 = 207.64 square feet. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not reflect the correct calculation for finding the area of half a circular garden with a radius of 11.5 feet.

2. Jonathan pays a $65 monthly flat rate for his cell phone. He is charged $0.12 per minute for each minute used in a roaming area. Which of the following expressions represents his monthly bill for x roaming minutes?

Correct answer: A

Rationale: The correct expression for Jonathan's monthly bill is 65 + 0.12x, where x represents the number of roaming minutes. The $65 monthly flat rate is added to the product of $0.12 per minute and the number of roaming minutes (x). Choice B is incorrect because it incorrectly multiplies the flat rate by x and adds the per-minute charge. Choice C is incorrect as it combines the flat rate and the per-minute charge into a single value. Choice D is incorrect as it incorrectly multiplies the flat rate by x and adds the per-minute charge separately.

3. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?

Correct answer: D

Rationale: To calculate the 30% increase, find 30% of 270 mg: 0.30 x 270 mg = 81 mg. Add this increase to the original dosage: 270 mg + 81 mg = 351 mg. Therefore, the patient's dosage after the 30% increase will be 351 mg. Choice A (81 mg) is incorrect as it only represents the calculated increase, not the total dosage post-increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is the original dosage plus 30 mg, not the correct calculation with a 30% increase.

4. Curtis measured the temperature of water in a flask in his science class. The temperature of the water was 35 °C. He carefully heated the flask so that the temperature of the water increased by about 2 °C every 3 minutes. Approximately how much had the temperature of the water increased after 20 minutes?

Correct answer: B

Rationale: To find the increase in temperature after 20 minutes, calculate how many 3-minute intervals are in 20 minutes (20 ÷ 3 = 6.66, rounding to 7 intervals). Then, multiply the temperature increase per interval (2 °C) by the number of intervals (7 intervals), giving a total increase of 14 °C. Therefore, after 20 minutes, the temperature of the water would have increased by approximately 14 °C. Choice A, 10 °C, is incorrect as it underestimates the total increase. Choice C, 15 °C, is incorrect as it overestimates the total increase. Choice D, 35 °C, is incorrect as it represents the initial temperature of the water, not the increase in temperature.

5. A gumball machine contains red, orange, yellow, green, and blue gumballs. Twenty percent of the gumballs are red, 30% are orange, 5% are yellow, 10% are green, and the rest are blue. If there are a total of 120 gumballs, how many more blue gumballs are there than yellow gumballs?

Correct answer: D

Rationale: The percentage of blue gumballs is 35% (100% - 20% - 30% - 5% - 10% = 35%). If there are 120 gumballs, 35% of that is 42 blue gumballs. Since 5% are yellow gumballs, which is 6 gumballs, the difference between 42 blue gumballs and 6 yellow gumballs is 36 more blue gumballs. Therefore, the correct answer is 36. Choice A (48) is incorrect as it miscalculates the difference. Choice B (30) is incorrect as it does not consider the correct percentage of blue gumballs. Choice C (42) is incorrect as it miscalculates the difference between blue and yellow gumballs.

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