ATI TEAS 7
TEAS Practice Test Math
1. An athlete runs 5 miles in 25 minutes and then changes pace to run the next 3 miles in 15 minutes. Overall, what is the average time in minutes it takes the athlete to run 1 mile?
- A. 7 minutes
- B. 5 minutes
- C. 6.5 minutes
- D. 8.5 minutes
Correct answer: B
Rationale: To find the average time per mile, add the total time taken to cover all miles and then divide by the total miles run. The athlete ran 5 miles in 25 minutes and 3 miles in 15 minutes, totaling 8 miles in 40 minutes. Therefore, the average time per mile is 40 minutes ÷ 8 miles = 5 minutes. Choice A, 7 minutes, is incorrect as it does not reflect the correct average time per mile. Choice C, 6.5 minutes, is incorrect since the calculation is not based on the given information. Choice D, 8.5 minutes, is incorrect as it does not represent the average time per mile for the entire run.
2. One roommate is saving to buy a house, so each month, he puts money aside in a special house savings account. The ratio of his monthly house savings to his rent is 1:3. If he pays $270 per month in rent, how much money does he put into his house savings account each month?
- A. $90
- B. $270
- C. $730
- D. $810
Correct answer: A
Rationale: The ratio of his savings to his rent is 1:3, which means that for every $3 he pays in rent, he saves $1 for the purchase of a house. To calculate the amount saved, divide $270 by 3: $270 ÷ 3 = $90. Therefore, he puts $90 into his house savings account each month. Choice B, $270, is incorrect because that is the amount he pays in rent, not the amount saved. Choices C and D, $730 and $810, are incorrect as they do not align with the 1:3 ratio described in the question.
3. Over several years, a real estate agent sold houses, with one year having an outlier where she sold 11 houses. Which of the following measures will most accurately reflect the number of houses she sold per year?
- A. mean
- B. median
- C. mode
- D. range
Correct answer: B
Rationale: The outlier of 11 would skew the data if the mean or range were used. The median, however, is not affected by outliers and is the most appropriate measure for reflecting the number of houses she sold per year. In this scenario, the data set does not have a mode as each value occurs only once, making mode not the most appropriate choice.
4. Mathew has to earn more than 96 points on his high school entrance exam in order to be eligible for varsity sports. Each question is worth 3 points, and the test has a total of 40 questions. Let x represent the number of test questions. How many questions can Mathew answer incorrectly and still qualify for varsity sports?
- A. x > 32
- B. x > 8
- C. 0 ≤ x < 8
- D. 0 ≤ x ≤ 8
Correct answer: C
Rationale: To determine the number of correct answers Mathew needs, solve the inequality: 3x > 96. This simplifies to x > 32. Therefore, Mathew must answer more than 32 questions correctly to qualify for varsity sports. Since the test consists of 40 questions, he can afford to answer at most 40 - 32 = 8 questions incorrectly. Therefore, the correct answer is 0 ≤ x < 8. Option A (x > 32) is incorrect as it suggests Mathew needs to answer more than 32 questions correctly, which is not the case. Option B (x > 8) is also incorrect as it does not account for the total number of questions in the test. Option D (0 ≤ x ≤ 8) is incorrect as it includes the possibility of answering all questions incorrectly, which is not allowed for Mathew to qualify for varsity sports.
5. As part of a study, a set of patients will be divided into three groups: 1/2 of the patients will be in Group Alpha, 1/3 of the patients will be in Group Beta, and 1/6 of the patients will be in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.
- A. Group Alpha, Group Beta, Group Gamma
- B. Group Alpha, Group Gamma, Group Beta
- C. Group Gamma, Group Alpha, Group Beta
- D. Group Gamma, Group Beta, Group Alpha
Correct answer: C
Rationale: The correct order from smallest to largest number of patients in each group is Group Gamma (1/6), Group Alpha (1/2), and Group Beta (1/3). Group Gamma has the smallest fraction of patients, followed by Group Alpha and then Group Beta. Therefore, choice C, 'Group Gamma, Group Alpha, Group Beta,' is the correct answer. Choices A, B, and D are incorrect because they do not follow the correct order based on the fractions of patients assigned to each group.
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