susan decided to celebrate getting her first nursing job by purchasing a new outfit she bought a dress for 6999 shoes for 3999 and accessories for 346
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Nursing Elites

ATI TEAS 7

TEAS Practice Math Test

1. Susan decided to celebrate getting her first nursing job by purchasing a new outfit. She bought a dress for $69.99, shoes for $39.99, and accessories for $34.67. What was the total cost of Susan’s outfit?

Correct answer: D

Rationale: To find the total cost of Susan's outfit, you need to add the prices of the dress, shoes, and accessories. $69.99 (dress) + $39.99 (shoes) + $34.67 (accessories) = $144.65. Therefore, the correct answer is $144.65. Option A ($69.99) is incorrect as it only represents the price of the dress. Option B ($75.31) is incorrect as it does not account for the total cost. Option C ($109.98) is incorrect as it does not include the individual prices of all items purchased.

2. A book has a width of 2.5 decimeters. What is the width of the book in centimeters?

Correct answer: B

Rationale: To convert decimeters to centimeters, we use the conversion factor that 1 decimeter is equal to 10 centimeters. Setting up the proportion: 1/0.1 = x/2.5. Solving for x gives 2.5 = 0.1x, x = 25. Therefore, the width of the book in centimeters is 25. Choices A, C, and D are incorrect because they do not correctly convert decimeters to centimeters. A and D have decimal placement errors, and C has an incorrect magnitude of centimeters.

3. The second midwife allocates 1/2 of her funds to pay an office administrator, plus another 1/10 for office supplies. What is the total fraction of the second midwife's budget that is spent on the office administrator and office supplies?

Correct answer: A

Rationale: To find the total fraction of the second midwife's budget spent on the office administrator and office supplies, add the fractions. The midwife allocates 1/2 of her funds to the office administrator (1/2) and another 1/10 for office supplies. Adding 1/2 and 1/10 gives a total of 3/5. Choice A (3/5) is correct. Choice B (2/12) is incorrect as it simplifies to 1/6, which is not the total fraction. Choice C (2/20) is incorrect as it simplifies to 1/10, which is only the fraction spent on office supplies, not the total. Choice D (1/20) is incorrect as it represents only the fraction spent on office supplies, not the total spent on both the administrator and supplies.

4. While at the local ice skating rink, Cora went around the rink 27 times in total. She slipped and fell 20 of the 27 times she skated around the rink. What approximate percentage of the times around the rink did Cora not slip and fall?

Correct answer: C

Rationale: To find the approximate percentage of the times Cora did not slip and fall, subtract the times she fell (20) from the total times around the rink (27), which gives 7. Then, divide the number of times she did not slip and fall (7) by the total times around the rink (27) and multiply by 100 to get the percentage. So, 7 divided by 27 equals 0.259, which rounds to approximately 26%. Therefore, the correct answer is 26%. Choice A (37%) is incorrect because it does not reflect the calculation based on the given information. Choice B (74%) is incorrect as it is not the result of the correct calculation. Choice D (15%) is incorrect as it does not match the calculated percentage based on the scenario provided.

5. A rectangular field has an area of 1452 square feet. If the length is three times the width, what is the width of the field?

Correct answer: A

Rationale: To find the width of the rectangular field, use the formula for the area of a rectangle: A = length × width. Given that the length is three times the width, you have A = 3w × w. Substituting the given area, 1452 = 3w^2. Solving for w, you get 484 = w^2. Taking the square root gives ±22, but since the width must be positive, the width of the field is 22 feet. Choice B, 44 feet, is incorrect because it represents the length, not the width. Choice C, 242 feet, is incorrect as it is not a factor of the area. Choice D, 1452 feet, is incorrect as it represents the total area of the field, not the width.

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