Nursing Elites

1. Solve for x: 2x + 6 = 14

• A. x = 4
• B. x = 8
• C. x = 10
• D. x = 13

Correct answer: A

Rationale: To solve the equation 2x + 6 = 14, you first subtract 6 from both sides to isolate 2x. This gives 2x = 8. Then, divide by 2 on both sides to find x. Therefore, x = 4. Choices B, C, and D are incorrect as they do not correctly follow the steps of solving the equation.

2. If x represents the width of a rectangle and the length is six less than two times the width, which of the following expressions represents the length of the rectangle in terms of x?

• A. 2x-6
• B. 6-2x
• C. 6x-2
• D. 3x-4

Correct answer: A

Rationale: To find the expression representing the length of the rectangle in terms of x, we need to consider that the length is six less than two times the width. If we denote the width as x, the length can be expressed as 2x - 6. Therefore, the correct expression is 2x-6 (choice A). Choice B, 6-2x, represents the width subtracted from 6, not the length. Choice C, 6x-2, is not derived from the given information about the relationship between the width and length. Choice D, 3x-4, is not consistent with the relationship provided in the question.

3. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?

• A. Histogram
• B. Pie chart
• C. Bar graph
• D. Scatter plot

Correct answer: A

Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.

4. University X requires some of its nursing students to take an exam before being admitted into the nursing program. In this year's class, the nursing students were required to take the exam, and all of those who took the exam passed. If this year's class has 200 students, how many students passed the exam?

• A. 120
• B. 100
• C. 60
• D. 50

Correct answer: B

Rationale: Since all nursing students who took the exam passed, it means 100% of the students who took the exam passed. As the total number of students in this year's class is 200, the number of students who passed the exam would be 100% of 200, equaling 200 * 100% = 200. Therefore, 200 students passed the exam.

5. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

• A. 4
• B. 7
• C. 8
• D. 13

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

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