Nursing Elites

1. In the winter of 2006, 6 inches of snow fell in Chicago, IL. The following winter, 3 inches of snowfall fell in Chicago. What was the percent decrease in snowfall in Chicago between those two winters?

• A. 69.40%
• B. 59.00%
• C. 41.00%
• D. 24.70%

Correct answer: C

Rationale: To calculate the percent decrease in snowfall between the two winters, use the formula: Percent Decrease = ((Initial Value - Final Value) / Initial Value) * 100. In this case, the initial value is 6 inches and the final value is 3 inches. Plug these values into the formula: ((6 - 3) / 6) * 100 = (3 / 6) * 100 = 0.5 * 100 = 50%. Therefore, the correct answer is 50%, which is not listed among the choices provided. Among the given choices, the closest percentage is 41.00%, which corresponds to choice C.

2. After taking a certain antibiotic, Dr. Lee observed that 30% of all his patients developed an infection. He further noticed that 5% of those patients required hospitalization to recover from the infection. What percentage of Dr. Lee’s patients were hospitalized after taking the antibiotic?

• A. 1.50%
• B. 5%
• C. 15%
• D. 30%

Correct answer: A

Rationale: To find the percentage of Dr. Lee's patients hospitalized, you need to calculate 5% of the 30% who developed an infection. 5% of 30% is 1.5%. Therefore, 1.5% of Dr. Lee's patients were hospitalized. Choice A is correct. Choices B, C, and D are incorrect because they do not accurately reflect the calculation of the percentage of patients requiring hospitalization after taking the antibiotic.

3. How many cubic inches of water could the aquarium hold if it were filled completely? (Dimensions: 30 in × 10 in × 12 in)

• A. 3600 cubic inches
• B. 52 cubic inches
• C. 312 cubic inches
• D. 1144 cubic inches

Correct answer: A

Rationale: To find the volume of the aquarium, we multiply its length, width, and height. The formula for the volume of a rectangular solid is V = l × w × h. Substituting the given dimensions, we get V = 30 × 10 × 12 = 3600 cubic inches. Therefore, the aquarium can hold 3600 cubic inches of water. Choice B (52 cubic inches), Choice C (312 cubic inches), and Choice D (1144 cubic inches) are incorrect as they do not correctly calculate the volume of the aquarium based on its dimensions.

4. If you pull an orange block from a bag of 3 orange, 5 green, and 4 purple blocks, what is the probability of consecutively pulling two more orange blocks without replacement?

• A. 1/12
• B. 3/55
• C. 1/55
• D. 2/33

Correct answer: B

Rationale: To calculate the probability of pulling two more orange blocks consecutively without replacement after the initial orange block is pulled, we need to multiply the probabilities. After the first orange block is pulled, there are 2 orange blocks left out of a total of 11 blocks remaining. So, the probability of pulling a second orange block is 2/11. Therefore, the overall probability is (3/12) * (2/11) = 3/55. Choice A (1/12) is incorrect because it only considers the probability of the first orange block being pulled. Choice C (1/55) is incorrect as it represents the probability of pulling two orange blocks in a row, not the consecutive pulls after the initial pull. Choice D (2/33) is incorrect as it does not reflect the correct calculation for the consecutive pulls of orange blocks.

5. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

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