ATI TEAS 7
TEAS Practice Math Test
1. The first midwife uses 2/5 of her monthly contribution to pay for rent and utilities. She saves half of the remainder for incidental expenditures, and uses the rest of the money to purchase medical supplies. How much money does she spend on medical supplies each month?
- A. $600
- B. $800
- C. $1,000
- D. $1,200
Correct answer: A
Rationale: The first midwife contributes $2000. She spends $800 on rent and utilities. After paying for rent and utilities, $1200 remains. Half of this amount, which is $600, is saved for incidental expenditures. Therefore, the first midwife spends the remaining $600 on purchasing medical supplies each month. Choice A, $600, is the correct answer. Choices B, C, and D are incorrect as they do not accurately reflect the amount spent on medical supplies as calculated in the given scenario.
2. Andy has already saved $15. He plans to save $28 per month. Which of the following equations represents the amount of money he will have saved?
- A. y = 15 + 28x
- B. y = 43x + 15
- C. y = 43x
- D. y = 28 + 15x
Correct answer: A
Rationale: The correct equation to represent the amount of money Andy will have saved is y = 15 + 28x. This is because Andy has already saved $15 and plans to save an additional $28 per month. Therefore, the total amount he will have saved can be calculated by adding the initial $15 to the monthly savings of $28 (28x), resulting in y = 15 + 28x. Choices B, C, and D do not correctly account for the initial $15 that Andy has saved and therefore do not represent the total amount correctly.
3. Two boxes are stacked, one measuring 4 inches tall and the other 6 inches tall. What is the total height of the stacked boxes?
- A. 10 inches
- B. 12 inches
- C. 8 inches
- D. 9 inches
Correct answer: A
Rationale: To find the total height of the stacked boxes, you need to add the height of each box together. Therefore, 4 inches (height of the first box) + 6 inches (height of the second box) = 10 inches, which is the total height of the stacked boxes. Choice B (12 inches) is incorrect because it adds the heights incorrectly. Choice C (8 inches) is incorrect as it does not consider both box heights. Choice D (9 inches) is incorrect as it also does not add the heights accurately.
4. Which of the following statements is true?
- A. The mean is less than the median
- B. The mode is greater than the median
- C. The mode is less than the mean, median, and range
- D. The mode is equal to the range
Correct answer: A
Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.
5. Given a double bar graph, which statement is true about the distributions of Group A and Group B?
- A. Group A is negatively skewed, Group B is normal.
- B. Group A is positively skewed, Group B is normal.
- C. Group A is positively skewed, Group B is neutral.
- D. Group A is normal, Group B is negatively skewed.
Correct answer: B
Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.
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