ATI TEAS 7
Practice Math TEAS TEST
1. How do you convert Fahrenheit to Celsius and Celsius to Fahrenheit?
- A. Fahrenheit to Celsius: Subtract 32, then divide by 1.8; Celsius to Fahrenheit: Multiply by 1.8, then add 32
- B. Fahrenheit to Celsius: Subtract 32, then divide by 2; Celsius to Fahrenheit: Multiply by 1.8, then add 20
- C. Fahrenheit to Celsius: Multiply by 2, then add 32; Celsius to Fahrenheit: Subtract 32, then divide by 1.8
- D. Fahrenheit to Celsius: Subtract 30, then divide by 1.8; Celsius to Fahrenheit: Multiply by 2, then add 32
Correct answer: A
Rationale: To convert Fahrenheit to Celsius, you start by subtracting 32 from the Fahrenheit temperature and then divide the result by 1.8. This formula accounts for the freezing point of water at 32°F and the conversion factor to Celsius. To convert Celsius to Fahrenheit, you multiply the Celsius temperature by 1.8 and then add 32. This process takes into consideration the conversion factor from Celsius to Fahrenheit and the freezing point of water. Choice B is incorrect as dividing by 2 instead of 1.8 would yield an inaccurate conversion. Choice C is incorrect as it involves incorrect operations for both conversions. Choice D is incorrect as subtracting 30 instead of 32 for Fahrenheit to Celsius and multiplying by 2 instead of 1.8 for Celsius to Fahrenheit would provide incorrect results.
2. A study divides patients into 3 groups with fractions: 1/2, 1/3, and 1/6. Which group has the largest number of patients?
- A. Alpha
- B. Beta
- C. Gamma
- D. Delta
Correct answer: A
Rationale: Group Alpha has the largest number of patients because it represents 1/2 of the total population, which is the highest fraction among the groups. Group Beta represents 1/3 of the population, and Group Gamma represents 1/6 of the population, making them smaller fractions in comparison. Group Delta is not mentioned in the question and is therefore unrelated to the comparison of the groups.
3. Simplify the following expression: (1/4) × (3/5) ÷ 1 (1/8)
- A. 8/15
- B. 27/160
- C. 2/15
- D. 27/40
Correct answer: C
Rationale: First, convert the mixed number 1 (1/8) into an improper fraction: 1 (1/8) = 9/8. Now, simplify the expression: (1/4) × (3/5) ÷ (9/8). To divide by a fraction, multiply by its reciprocal: (1/4) × (3/5) × (8/9) = 24/180 = 2/15. Thus, the simplified expression is 2/15. Choice A (8/15) is incorrect because the correct answer is 2/15. Choice B (27/160) is incorrect as it is not the result of the given expression. Choice D (27/40) is incorrect as it does not match the simplified expression obtained.
4. Alan currently weighs 200 pounds, but he wants to lose weight to get down to 175 pounds. What is the difference in kilograms? (1 pound is approximately equal to 0.45 kilograms.)
- A. 9 kg
- B. 11.25 kg
- C. 78.75 kg
- D. 90 kg
Correct answer: B
Rationale: The difference between Alan's current weight of 200 pounds and his goal weight of 175 pounds is 25 pounds (200 pounds - 175 pounds). To convert pounds to kilograms, you multiply the number of pounds by 0.45 (not divide by 2.2). Thus, 25 pounds is approximately 11.25 kilograms (25 pounds x 0.45). Therefore, the difference in kilograms is 11.25 kg. Choice A is incorrect because it miscalculates the conversion. Choices C and D are significantly higher values and do not reflect the correct conversion from pounds to kilograms.
5. The scatter plot below shows the relationship between the students' exam scores and their heights. Which type of correlation is depicted in the scatter plot?
- A. Positive
- B. Positive and Negative
- C. Negative
- D. No correlation
Correct answer: D
Rationale: The scatter plot illustrates the relationship between students' exam scores and heights. There is no correlation between these variables, as height is not expected to have a direct impact on exam scores. Therefore, choice D, 'No correlation,' is the correct answer. Choices A, 'Positive,' and C, 'Negative,' are incorrect because the scatter plot does not indicate a positive or negative correlation between exam scores and heights. Choice B, 'Positive and Negative,' is also incorrect because the scatter plot does not exhibit both positive and negative correlations simultaneously.
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