ATI TEAS 7
TEAS Test Practice Math
1. Order the groups from largest to smallest, according to the number of doctors in each group.
- A. Group X, Group Y, Group Z
- B. Group Z, Group Y, Group X
- C. Group Z, Group X, Group Y
- D. Group Y, Group X, Group Z
Correct answer: B
Rationale: The correct order from largest to smallest number of doctors in each group is Group Z (20 doctors), Group Y (15 doctors), and Group X (10 doctors). Therefore, the correct order is Group Z, Group Y, and Group X, which matches option B. Option B is correct because it correctly reflects the descending order of the number of doctors in each group. Options A, C, and D are incorrect as they do not follow the correct order of the number of doctors in each group.
2. 4 − 1/(22) + 24 ÷ (8 + 12). Simplify the expression. Which of the following is correct?
- A. 1.39
- B. 2.74
- C. 4.95
- D. 15.28
Correct answer: C
Rationale: First, complete the operations in parentheses: 4 − (1/22) + 24 ÷ 20. Next, simplify the exponents: 4 − (1/22) + 24 ÷ 20 = 4 − (1/4) + 24 ÷ 20. Then, complete multiplication and division operations: 4 − (1/4) + 24 ÷ 20 = 4 − 0.25 + 1.2. Finally, complete addition and subtraction operations: 4 − 0.25 + 1.2 = 4.95. Choice A, 1.39, is incorrect as it does not match the correct calculation. Choice B, 2.74, is incorrect as it is not the result of the given expression. Choice D, 15.28, is incorrect as it is not the correct simplification of the initial expression.
3. In the winter of 2006, 6 inches of snow fell in Chicago, IL. The following winter, 3 inches of snowfall fell in Chicago. What was the percent decrease in snowfall in Chicago between those two winters?
- A. 69.40%
- B. 59.00%
- C. 41.00%
- D. 24.70%
Correct answer: C
Rationale: To calculate the percent decrease in snowfall between the two winters, use the formula: Percent Decrease = ((Initial Value - Final Value) / Initial Value) * 100. In this case, the initial value is 6 inches and the final value is 3 inches. Plug these values into the formula: ((6 - 3) / 6) * 100 = (3 / 6) * 100 = 0.5 * 100 = 50%. Therefore, the correct answer is 50%, which is not listed among the choices provided. Among the given choices, the closest percentage is 41.00%, which corresponds to choice C.
4. During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?
- A. 15 shifts
- B. 14 shifts
- C. 16 shifts
- D. 17 shifts
Correct answer: B
Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).
5. Solve for y: 2y + 5 = 25 * 10
- A. y = 25
- B. y = 100
- C. y = 150
- D. y = 200
Correct answer: B
Rationale: To solve the equation 2y + 5 = 25 * 10, start by simplifying the right side: 25 * 10 = 250. Then, subtract 5 from both sides to isolate 2y: 2y = 250 - 5 = 245. Finally, divide by 2 to find the value of y: y = 245 / 2 = 122.5. Therefore, the correct answer is y = 122.5. Choices A, C, and D are incorrect as they do not result from the correct calculation steps.
Similar Questions
Access More Features
ATI TEAS Premium Plus
$149.99/ 90 days
- Actual ATI TEAS 7 Questions
- 3,000 questions with answers
- 90 days access
ATI TEAS Basic
$49/ 30 days
- 3,000 Questions with answers
- 30 days access