during january dr lewis worked 20 shifts during february she worked three times as many shifts as she did during january during march she worked half

ATI TEAS 7

TEAS 7 Math Practice Test

1. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?

A. shifts = 20 + 3 + 1/2
B. shifts = (20)(3)(1/2)
C. shifts = (20)(3) + 1/2
D. shifts = 20 + (3)(1/2)

Correct answer: B

Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.

2. If , then

A. 1
B. 2
C. 3
D. 4

Correct answer: C

Rationale: If $2x = 6$, then solving for $x$, we have $x = \frac{6}{2} = 3$. So, if $x = 3$, then $x+1 = 3+1 = 4$. Therefore, the value of $x+1$ would be 4.

3. Simplify the expression. Which of the following is the value of x? (5(4x – 5) = (3/2)(2x – 6))

A. −(2/7)
B. −(4/17)
C. (16/17)
D. (8/7)

Correct answer: C

Rationale: To solve the given proportion 5(4x – 5) = (3/2)(2x – 6), first distribute to get 20x - 25 = 3x - 9. Then, simplify the linear equation by isolating x: 20x - 3x = 25 - 9, which leads to 17x = 16. Finally, solving for x gives x = 16/17. Choice A is incorrect as it does not match the calculated value of x. Choice B is incorrect as it does not correspond to the correct solution for x. Choice D is incorrect as it does not align with the accurate value of x obtained from solving the equation.

4. How do you find the least common multiple?

A. List all multiples of the numbers, then find the smallest common one
B. List all factors of the numbers, then find the largest common one
C. Divide the largest number by the smallest
D. Multiply the two numbers together

Correct answer: A

Rationale: The correct way to find the least common multiple is to list all the multiples of each number and then identify the smallest common multiple. Choice A is correct because it describes the correct process. Listing factors, as suggested in choice B, helps in finding the greatest common factor, not the least common multiple. Dividing the largest number by the smallest, as mentioned in choice C, does not help find the least common multiple. Multiplying the two numbers together, as stated in choice D, results in their least common multiple when the numbers have no common factors.

5. What is the median of the data set: 3, 5, 7, 9, 11?

A. 3
B. 7
C. 9
D. 5

Correct answer: B

Rationale: To find the median of a set of numbers, you arrange them in ascending order and then find the middle value. Given the data set 3, 5, 7, 9, 11, when arranged in ascending order, becomes 3, 5, 7, 9, 11. The middle value in this set is 7, making it the median. Choice A (3) is the smallest value, not the middle value. Choice C (9) and Choice D (5) are not the middle values of the set either. Therefore, the correct answer is B (7).