during january dr lewis worked 20 shifts during february she worked three times as many shifts as she did during january during march she worked half

ATI TEAS 7

TEAS 7 Math Practice Test

1. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?

A. shifts = 20 + 3 + 1/2
B. shifts = (20)(3)(1/2)
C. shifts = (20)(3) + 1/2
D. shifts = 20 + (3)(1/2)

Correct answer: B

Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.

2. Which statement about multiplication and division is true?

A. The product of the quotient and the dividend is the divisor.
B. The product of the dividend and the divisor is the quotient.
C. The product of the quotient and the divisor is the dividend.
D. None of the above.

Correct answer: C

Rationale: In division, the dividend is the number being divided, the divisor is the number you are dividing by, and the quotient is the result. Multiplying the quotient by the divisor gives the original dividend. This is the reverse of the division operation. Therefore, the correct statement is that the product of the quotient and the divisor equals the dividend, making option C correct. Choices A and B provide incorrect relationships between the terms dividend, divisor, quotient, and product, making them inaccurate. Option D is a general statement that does not provide the correct relationship between multiplication and division terms.

3. Round to the nearest tenth: 8.067.

A. 8.07
B. 8.1
C. 8
D. 8.11

Correct answer: A

Rationale: When rounding a number to the nearest tenth, you look at the digit in the hundredths place. Since 8.067 has a 6 in the hundredths place, which is equal to or greater than 5, you round the tenths place up by 1. Therefore, rounding 8.067 to the nearest tenth gives 8.07. Choice B (8.1) would be incorrect because 8.067 is closer to 8.1 than to 8, but it's not quite there. Choice C (8) is incorrect as it would be rounding down, and Choice D (8.11) is incorrect as it is rounding to the nearest hundredth, not the nearest tenth.

4. Solve the following equation: 3(2y+50)−4y=500

A. y = 125
B. y = 175
C. y = 150
D. y = 200

Correct answer: B

Rationale: To solve the equation 3(2y+50)−4y=500, first distribute to get 6y+150−4y=500. Combining like terms results in 2𝑦 + 150 = 500. By subtracting 150 from both sides, we get 2y = 350. Dividing by 2 gives y = 175. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not correctly follow the steps of distributing, combining like terms, and isolating the variable to solve for y.

5. What is the median of the data set: 3, 5, 7, 9, 11?

A. 3
B. 7
C. 9
D. 5

Correct answer: B

Rationale: To find the median of a set of numbers, you arrange them in ascending order and then find the middle value. Given the data set 3, 5, 7, 9, 11, when arranged in ascending order, becomes 3, 5, 7, 9, 11. The middle value in this set is 7, making it the median. Choice A (3) is the smallest value, not the middle value. Choice C (9) and Choice D (5) are not the middle values of the set either. Therefore, the correct answer is B (7).