ATI TEAS 7
TEAS Exam Math Practice
1. Anna is buying fruit at the farmers’ market. She selects 1.2 kilograms of apples, 800 grams of bananas, and 300 grams of strawberries. The farmer charges her a flat rate of $4 per kilogram. What is the total cost of her produce?
- A. $4.40
- B. $5.24
- C. $9.20
- D. $48.80
Correct answer: C
Rationale: To calculate the total cost, convert all weights to kilograms. 800 grams = 0.8 kilograms; 300 grams = 0.3 kilograms. Add up the weights: 1.2 kg + 0.8 kg + 0.3 kg = 2.3 kg. Multiply the total weight by the cost per kilogram: 2.3 kg Ă— $4/kg = $9.20. Therefore, the total cost of her produce is $9.20. Choice A, $4.40, is incorrect as it does not account for the total weight of all the fruits. Choice B, $5.24, is incorrect as it does not accurately calculate the total cost based on the given weights and price per kilogram. Choice D, $48.80, is incorrect as it is significantly higher than the correct total cost and suggests an incorrect calculation method.
2. What is the value of the sum of 3/4 and 5/8?
- A. 1 3/8
- B. 1 1/2
- C. 1 7/8
- D. 1 5/8
Correct answer: D
Rationale: To find the sum of fractions, they need to have a common denominator. In this case, the common denominator is 8. So, 3/4 = 6/8. Adding 6/8 and 5/8 gives 11/8, which simplifies to 1 3/8. Therefore, the correct answer is 1 3/8, which corresponds to choice A. Choices B, C, and D are incorrect as they do not represent the correct sum of 3/4 and 5/8.
3. Five of six numbers have a sum of 25. The average of all six numbers is 6. What is the sixth number?
- A. 8
- B. 10
- C. 11
- D. 12
Correct answer: C
Rationale: To find the sum of all six numbers, we multiply the average (6) by the total numbers (6), which equals 36. Since the sum of five numbers is 25, the sixth number can be found by subtracting the sum of five numbers from the total sum: 36 - 25 = 11. Therefore, the sixth number is 11. Choice A, 8, is incorrect because adding 8 to the sum of five numbers (25) would result in a total greater than the correct sum of all six numbers (36). Choice B, 10, is incorrect because adding 10 to the sum of five numbers (25) would also result in a total greater than the correct sum of all six numbers (36). Choice D, 12, is incorrect because adding 12 to the sum of five numbers (25) would exceed the correct sum of all six numbers (36).
4. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?
- A. $1.75
- B. $2.00
- C. $2.25
- D. $2.50
Correct answer: C
Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.
5. What is a common denominator?
- A. A shared multiple of two denominators
- B. A shared factor of two numerators
- C. A number that is the same in all fractions
- D. A number that divides evenly into both fractions
Correct answer: A
Rationale: A common denominator is a shared multiple of the denominators in a set of fractions. It is necessary when adding or subtracting fractions to have a common denominator to ensure that the fractions can be combined accurately. Choice B is incorrect because the common denominator is related to the denominators, not the numerators. Choice C is incorrect because while the common denominator is the same in all fractions being added or subtracted, it is not necessarily a number that is the same in all fractions. Choice D is incorrect because a common denominator is a multiple of the denominators, not a number that divides evenly into both fractions.
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