ATI TEAS 7
TEAS Exam Math Practice
1. Anna is buying fruit at the farmers’ market. She selects 1.2 kilograms of apples, 800 grams of bananas, and 300 grams of strawberries. The farmer charges her a flat rate of $4 per kilogram. What is the total cost of her produce?
- A. $4.40
- B. $5.24
- C. $9.20
- D. $48.80
Correct answer: C
Rationale: To calculate the total cost, convert all weights to kilograms. 800 grams = 0.8 kilograms; 300 grams = 0.3 kilograms. Add up the weights: 1.2 kg + 0.8 kg + 0.3 kg = 2.3 kg. Multiply the total weight by the cost per kilogram: 2.3 kg × $4/kg = $9.20. Therefore, the total cost of her produce is $9.20. Choice A, $4.40, is incorrect as it does not account for the total weight of all the fruits. Choice B, $5.24, is incorrect as it does not accurately calculate the total cost based on the given weights and price per kilogram. Choice D, $48.80, is incorrect as it is significantly higher than the correct total cost and suggests an incorrect calculation method.
2. A recipe calls for 2.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?
- A. 5.33 mL
- B. 7.43 mL
- C. 12.325 mL
- D. 0.507 mL
Correct answer: C
Rationale: To convert 2.5 teaspoons of vanilla to milliliters, you multiply by the conversion factor: 2.5 teaspoons * 4.93 mL = 12.325 mL. Therefore, the correct amount of vanilla in milliliters is 12.325 mL. Choice A (5.33 mL) is incorrect because it does not account for the correct conversion factor. Choice B (7.43 mL) is incorrect as it also does not use the accurate conversion factor. Choice D (0.507 mL) is incorrect as it represents a miscalculation of the conversion.
3. Given the double bar graph shown below, which of the following statements is true?
- A. Group A is negatively skewed, while Group B is approximately normal.
- B. Group A is positively skewed, while Group B is approximately normal.
- C. Group A is approximately normal, while Group B is negatively skewed.
- D. Group A is approximately normal, while Group B is positively skewed.
Correct answer: B
Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.
4. If Hannah spends at least $16 on 4 packages of coffee, which of the following inequalities represents the possible costs?
- A. 16 ≥ 4p
- B. 16 < 4p
- C. 16 > 4p
- D. 16 ≤ 4p
Correct answer: D
Rationale: To represent the relationship between the number of packages of coffee and the minimum cost, the inequality can be written as 4p ≥ 16 (cost is at least $16). This inequality can also be expressed as 16 ≤ 4p, which reads as the cost being less than or equal to $16. Therefore, the correct answer is D. Choice A (16 ≥ 4p) implies that the cost can be greater than or equal to $16, which does not align with the statement that Hannah spends at least $16. Choice B (16 < 4p) suggests that the cost is less than $16, which contradicts the given information. Choice C (16 > 4p) indicates that the cost is greater than $16, which is not accurate based on the scenario provided.
5. What is 31% of 426?
- A. 425.69
- B. 132.06
- C. 13.7
- D. 0.07
Correct answer: B
Rationale: To find 31% of 426, multiply 0.31 by 426. This gives 0.31 × 426 = 132.06. Therefore, choice B, 132.06, is the correct answer. Choice A, 425.69, is close to the original number but is not the correct answer for the percentage calculation. Choice C, 13.7, is not the correct result for 31% of 426. Choice D, 0.07, is significantly lower than the correct answer and does not represent 31% of 426.
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