ATI TEAS 7
TEAS Math Practice Test
1. When rounding 245.2678 to the nearest thousandth, which place value would be used to decide whether to round up or round down?
- A. Ten-thousandths
- B. Thousandths
- C. Hundredths
- D. Thousand
Correct answer: A
Rationale: When rounding a number to the nearest thousandth, you look at the digit in the ten-thousandths place to determine whether to round up or down the digit in the thousandths place. In this case, rounding 245.2678 to the nearest thousandth, the digit in the ten-thousandths place is 6, which is greater than or equal to 5, so you would round up the digit in the thousandths place. Therefore, the correct answer is the ten-thousandths place. Choices B, C, and D are incorrect because they do not directly influence the rounding of the thousandths place in this scenario.
2. A homeowner has hired two people to mow his lawn. If person A is able to mow the lawn in 2 hours by herself and person B is able to mow the lawn in 3 hours by himself, what is the amount of time it would take for both person A and B to mow the lawn together?
- A. 5 hours
- B. 2.5 hours
- C. 1.2 hours
- D. 1 hour
Correct answer: C
Rationale: To find the combined work rate, you add the individual work rates: 1/2 + 1/3 = 5/6. This means that together, they can mow 5/6 of the lawn per hour. To determine how long it would take for both A and B to mow the entire lawn, you take the reciprocal of 5/6, which gives you 6/5 or 1.2 hours. Therefore, it would take 1.2 hours for person A and person B to mow the lawn together. Choice A (5 hours) is incorrect because it does not consider the combined efficiency of both workers. Choice B (2.5 hours) is incorrect as it does not reflect the correct calculation based on the combined work rates of the two individuals. Choice D (1 hour) is incorrect as it doesn't consider the fact that the combined rate is less than the individual rate of person A alone, thus taking longer than 1 hour.
3. Given a double bar graph, which statement is true about the distributions of Group A and Group B?
- A. Group A is negatively skewed, Group B is normal.
- B. Group A is positively skewed, Group B is normal.
- C. Group A is positively skewed, Group B is neutral.
- D. Group A is normal, Group B is negatively skewed.
Correct answer: B
Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.
4. How do you find the factors of a number?
- A. Divide the number by all possible numbers
- B. Find all pairs of numbers that multiply to give the number
- C. List all the multiples of the number
- D. Add the digits of the number together
Correct answer: B
Rationale: The correct way to find the factors of a number is to identify all pairs of numbers that, when multiplied together, result in the given number. This method allows you to determine all the factors of the number. Choice A is incorrect because dividing the number by all possible numbers is not an efficient way to find its factors. Choice C is incorrect as listing all the multiples of the number does not give the factors. Choice D is unrelated to finding factors as adding the digits of a number together does not provide information about its factors.
5. A study about anorexia was conducted on 100 patients. 70% were women, and 10% of the men were overweight as children. How many male patients were not overweight as children?
- A. 3
- B. 10
- C. 27
- D. 30
Correct answer: C
Rationale: Out of the 100 patients, 30% were men, which equals 30 male patients. It is given that 10% of the men were overweight as children, so 10% of 30 is 3, meaning 3 male patients were overweight. Therefore, the remaining 27 male patients were not overweight as children. Choice A, B, and D are incorrect as they do not accurately represent the number of male patients who were not overweight.
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