ATI TEAS 7
TEAS Practice Math Test
1. A lab technician took 100 hairs from a patient to conduct several tests. The technician used 1/7 of the hairs for a drug test. How many hairs were used for the drug test? (Round your answer to the nearest hundredth.)
- A. 14
- B. 14.2
- C. 14.29
- D. 14.3
Correct answer: C
Rationale: To find how many hairs were used for the drug test, you need to calculate 1/7 of 100. 1/7 of 100 is 14.2857, which rounds to 14.29 when rounded to the nearest hundredth. Therefore, 14.29 hairs were used for the drug test. Choice A is incorrect as it does not account for rounding to the nearest hundredth. Choices B and D are incorrect as they do not accurately reflect the calculated value after rounding.
2. Four more than a number is 2 less than 5\6 of another number. Which equation represents this?
- A. x + 4 = 5\6y - 2
- B. x + 4 = 2 - 5\6y
- C. 4 + x = 5\6y + 2
- D. x + 4 = 5\6y - 2
Correct answer: A
Rationale: The equation that represents the relationship is x + 4 = 5\6y - 2.
3. Erma has her eye on two sweaters, one for $50 and one for $44. With a sale of 25% off the cheaper item, what will she spend?
- A. 79
- B. 81
- C. 83
- D. 85
Correct answer: A
Rationale: Erma pays full price for the $50 sweater and gets 25% off the $44 sweater. 25% of $44 is $11, so she pays $33 for the second sweater. Therefore, the total amount Erma spends is $50 (first sweater) + $33 (second sweater) = $79. Choices B, C, and D are incorrect as they do not correctly calculate the total amount Erma would spend on both sweaters.
4. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?
- A. Histogram
- B. Pie chart
- C. Bar graph
- D. Scatter plot
Correct answer: A
Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.
5. In a study on anorexia, 100 patients participated. Among them, 70% were women, and 10% of the men were overweight as children. How many male patients in the study were not overweight as children?
- A. 3
- B. 10
- C. 27
- D. 30
Correct answer: C
Rationale: Out of the 100 patients, 30% were men. Since 10% of the men were overweight as children, 90% of the male patients were not overweight. Therefore, the number of male patients not overweight as children can be calculated as 30 (total male patients) x 0.90 = 27. Choices A, B, and D are incorrect because they do not accurately calculate the number of male patients who were not overweight as children based on the given information.
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