ATI TEAS 7
TEAS Practice Math Test
1. A lab technician took 100 hairs from a patient to conduct several tests. The technician used 1/7 of the hairs for a drug test. How many hairs were used for the drug test? (Round your answer to the nearest hundredth.)
- A. 14
- B. 14.2
- C. 14.29
- D. 14.3
Correct answer: C
Rationale: To find how many hairs were used for the drug test, you need to calculate 1/7 of 100. 1/7 of 100 is 14.2857, which rounds to 14.29 when rounded to the nearest hundredth. Therefore, 14.29 hairs were used for the drug test. Choice A is incorrect as it does not account for rounding to the nearest hundredth. Choices B and D are incorrect as they do not accurately reflect the calculated value after rounding.
2. One gallon of cleaning solution requires 6 oz of ammonia. If the maintenance department needs 230 gallons of solution to clean all of the floors, how much ammonia is needed?
- A. 1380 gallons
- B. 6900 gallons
- C. 1380 oz
- D. 1400 oz
Correct answer: C
Rationale: To find out how much ammonia is needed for 230 gallons of cleaning solution, you multiply the amount of ammonia needed per gallon by the total gallons of solution required. Therefore, 230 gallons * 6 oz/gallon = 1380 oz of ammonia. Option A ('1380 gallons') and Option B ('6900 gallons') are incorrect as the question asks for the amount of ammonia needed, not the total volume of cleaning solution. Option D ('1400 oz') is incorrect as it does not correctly calculate the amount of ammonia required based on the given information.
3. What is the solution to 4 x 7 + (25 – 21)²?
- A. 512
- B. 36
- C. 44
- D. 22
Correct answer: C
Rationale: To find the solution, first solve the expression inside the parentheses: 25 - 21 = 4. Then, square the result from the parentheses: 4² = 16. Next, perform the multiplication: 4 x 7 = 28. Finally, add the results: 28 + 16 = 44. Therefore, the correct answer is 44. Choice A (512), Choice B (36), and Choice D (22) are incorrect as they do not follow the correct order of operations for solving the given mathematical expression.
4. Given a double bar graph, which statement is true about the distributions of Group A and Group B?
- A. Group A is negatively skewed, Group B is normal.
- B. Group A is positively skewed, Group B is normal.
- C. Group A is positively skewed, Group B is neutral.
- D. Group A is normal, Group B is negatively skewed.
Correct answer: B
Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.
5. A person drives 300 miles at 60 mph, then another 200 miles at 80 mph, with a 30-minute break. How long does the trip take?
- A. 5.5 hours
- B. 7 hours
- C. 6 hours
- D. 4.5 hours
Correct answer: C
Rationale: To find the total time, we calculate the time taken for each segment: 300 miles at 60 mph = 300 miles ÷ 60 mph = 5 hours; 200 miles at 80 mph = 200 miles ÷ 80 mph = 2.5 hours. Adding these gives 5 hours + 2.5 hours = 7.5 hours. Converting the 30-minute break to hours (30 minutes ÷ 60 = 0.5 hours), the total time taken is 7.5 hours + 0.5 hours = 8 hours. Therefore, the correct answer is not among the given choices. The rationale provided in the original question is incorrect as it does not account for the break time and has a calculation error in adding the individual times.
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