Nursing Elites

1. A closet is filled with red, blue, and green shirts. If 1/4 of the shirts are green and 1/3 are red, what fraction of the shirts are blue?

• A. 1/2
• B. 1/3
• C. 5/12
• D. 1/4

Correct answer: C

Rationale: Let the total number of shirts be x. Given that 1/4 of the shirts are green and 1/3 are red, we have Green = x/4 and Red = x/3. To find the fraction of blue shirts, we subtract the fractions of green and red shirts from 1: Blue fraction = 1 - (1/4 + 1/3) = 1 - (3/12 + 4/12) = 1 - 7/12 = 5/12. Therefore, the fraction of blue shirts is 5/12. Choices A, B, and D are incorrect because they do not accurately represent the fraction of blue shirts given the information provided.

2. Which of the following best describes the data set below? 1, 1, 2, 2, 2, 2, 3, 3, 7, 7, 8, 8, 8, 8, 9, 9

• A. Uniform
• B. Right-skewed
• C. Bimodal
• D. Left-skewed

Correct answer: C

Rationale: The correct answer is C: Bimodal. A bimodal distribution has two distinct peaks or modes. In this data set, the numbers 2 and 8 appear more frequently than other numbers, creating two modes (2 and 8). Choices A, B, and D are incorrect. Option A, 'Uniform,' describes a distribution where all values have equal frequency, which is not the case in this data set. Options B and D, 'Right-skewed' and 'Left-skewed,' refer to distributions where the data is skewed towards one side, which is not observed in this dataset. Therefore, the data set is best described as bimodal.

3. Express 18/5 as a reduced mixed number.

• A. 3 3/5
• B. 3 1/15
• C. 3 1/18
• D. 3 1/54

Correct answer: A

Rationale: 18/5 = 3 with a remainder of 3, so it is 3 3/5. 3 1/15 is equivalent to 46/15 which is greater than 18/5 3 1/18 converts to 55/18 which is also greater than 18/5 3 1/54 converts to 163/54

4. Two boxes are stacked, one measuring 4 inches tall and the other 6 inches tall. What is the total height of the stacked boxes?

• A. 10 inches
• B. 12 inches
• C. 8 inches
• D. 9 inches

Correct answer: A

Rationale: To find the total height of the stacked boxes, you need to add the height of each box together. Therefore, 4 inches (height of the first box) + 6 inches (height of the second box) = 10 inches, which is the total height of the stacked boxes. Choice B (12 inches) is incorrect because it adds the heights incorrectly. Choice C (8 inches) is incorrect as it does not consider both box heights. Choice D (9 inches) is incorrect as it also does not add the heights accurately.

5. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?

• A. 3/12
• B. 3/55
• C. 2/10
• D. 1/3

Correct answer: B

Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.

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