Nursing Elites

1. When is a histogram preferred over a bar graph?

• A. Comparison between categories
• B. Frequency
• C. Percentages
• D. Proportions

Correct answer: B

Rationale: Histograms are specifically designed to display the frequency distribution of continuous data, showing the distribution of values over intervals or bins. On the other hand, bar graphs are used to compare different categories or discrete data points. Therefore, the correct answer is B. Choices A, C, and D are incorrect because histograms are not primarily used for comparing categories, percentages, or proportions, but rather for visualizing the distribution of frequencies within data intervals.

2. Kyle has $950 in savings and wishes to donate one-fifth of it to 8 local charities. He estimates that he will donate around $30 to each charity. Which of the following correctly describes the reasonableness of his estimate?

• A. It is reasonable because $190 is one-fifth of $950
• B. It is reasonable because $190 is less than one-fifth of $1,000
• C. It is not reasonable because $240 is more than one-fifth of $1,000
• D. It is not reasonable because $240 is one-fifth of $1,000

Correct answer: C

Rationale: Kyle initially had $950 in savings, and one-fifth of that amount would be $190. Since he wishes to donate around $30 to each charity, the total amount he would donate to 8 local charities would be $30 x 8 = $240. This amount is more than one-fifth of $1,000, making the estimate not reasonable. Choice A is incorrect because $190 is the correct one-fifth of $950, not $900. Choice B is incorrect as it compares $190 to a different amount ($1,000) rather than the actual total. Choice D is incorrect as it states that $240 is one-fifth of $1,000, which is inaccurate.

3. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

4. Which statement about the following set is true? {60, 5, 18, 20, 37, 37, 11, 90, 72}

• A. The median and the mean are equal.
• B. The mean is less than the mode.
• C. The mode is greater than the median.
• D. The median is less than the mean.

Correct answer: D

Rationale: To find the median, we first need to arrange the set in ascending order: {5, 11, 18, 20, 37, 37, 60, 72, 90}. The median is the middle value, which is 37 in this case. The mean is calculated by adding all numbers and dividing by the total count, which gives a mean greater than 37. Therefore, the statement that the median is less than the mean is correct. Choice A is incorrect because the median and mean are not equal in this set. Choice B is incorrect as the mean is greater than the mode in this set. Choice C is incorrect as the mode is 37, which is equal to the median, not greater.

5. Approximately how many people voted for the proposition if 9.5% of the town's population of 51,623 voted for it in a municipal election?

• A. 3,000
• B. 5,000
• C. 7,000
• D. 10,000

Correct answer: B

Rationale: To find the approximate number of people who voted for the proposition, multiply the town's population by the percentage that voted for it. 9.5% of 51,623 is about 0.095 * 51,623 ≈ 4,904. Rounded to the nearest thousand, this gives an estimate of 5,000 people. Therefore, choice B, '5,000,' is the correct answer. Choices A, C, and D are incorrect as they do not align with the calculated estimation.

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