Nursing Elites

1. The length of a rectangle is 3 times its width. If the width is 4 inches, what is the perimeter of the rectangle?

• A. 28 inches
• B. 24 inches
• C. 30 inches
• D. 32 inches

Correct answer: A

Rationale: To find the perimeter of a rectangle, you add up all its sides. Given that the width is 4 inches and the length is 3 times the width (3 * 4 = 12 inches), the perimeter formula is 2 * (length + width). Substituting the values, we get 2 * (12 + 4) = 2 * 16 = 32 inches. Therefore, the correct answer is 32 inches. Choices B, C, and A are incorrect because they do not reflect the correct calculation of the rectangle's perimeter.

2. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

• A. (1.8, 3.6) and (-1.8, -3.6)
• B. (1.8, -3.6) and (-1.8, 3.6)
• C. (1.3, 2.6) and (-1.3, -2.6)
• D. (-1.3, 2.6) and (1.3, -2.6)

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

3. What score must Dwayne get on his next math test to maintain an overall average of at least 90?

• A. 89
• B. 98
• C. 95
• D. 100

Correct answer: B

Rationale: To maintain an overall average of at least 90, Dwayne must aim for a score of 90 on every test. If his current average is below 90, he needs to make up for it by scoring higher on upcoming tests. Choosing 98 ensures that his overall average remains at or above 90. Choice A (89) is below the desired average of 90, so it would not be sufficient. Choices C (95) and D (100) are higher than necessary to maintain an average of at least 90.

4. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?

• A. $1.75
• B. $2.00
• C. $2.25
• D. $2.50

Correct answer: C

Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.

5. In Mrs. McConnell's classroom, there are 5 students with hazel eyes and 2 students with green eyes out of a total of 30 students. What percentage of the students have either hazel or green eyes?

• A. 0.23
• B. 0.3
• C. 0.47
• D. 0.77

Correct answer: A

Rationale: To calculate the percentage of students with either hazel or green eyes, add the number of students with hazel and green eyes (5 + 2 = 7) and divide by the total number of students (30): 7 ÷ 30 ≈ 0.23 or 23%. The correct answer is A, 0.23, which represents 23% of the total students. Choice B, 0.3, is incorrect as it corresponds to 30%, which is higher than the total number of students. Choice C, 0.47, is incorrect as it represents 47%, which is also higher than the total number of students. Choice D, 0.77, is incorrect as it corresponds to 77%, which is much higher than the total number of students.

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