Nursing Elites

1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

2. On a highway map, the scale indicates that 1 inch represents 45 miles. If the distance on the map is 3.2 inches, how far is the actual distance in miles?

• A. 144 miles
• B. 160 miles
• C. 180 miles
• D. 200 miles

Correct answer: A

Rationale: To find the actual distance in miles, you need to set up a proportion using the scale provided (1 inch = 45 miles). Since the distance on the map is 3.2 inches, you can set up the proportion: 1 inch / 45 miles = 3.2 inches / x miles. Cross-multiply to solve for x: 1 * x = 45 * 3.2, x = 144. Therefore, the actual distance in miles is 144. Choices B, C, and D are incorrect because they do not accurately calculate the actual distance using the scale provided.

3. Three roommates decided to combine their money to buy a birthday gift for the fourth roommate. The first roommate contributed $12.03, the second roommate gave $11.96, and the third roommate donated $12.06. Estimate the total amount of money the roommates used to purchase the gift

• A. $34
• B. $35
• C. $36
• D. $37

Correct answer: C

Rationale: To find the total amount contributed, you can add the individual contributions: $12.03 + $11.96 + $12.06 = $36. Therefore, the roommates used a total of $36 to purchase the gift. Choice A ($34), B ($35), and D ($37) are incorrect as they do not reflect the accurate total amount contributed by the roommates.

4. The hypotenuse (side C) of a triangle is 13 inches long. Which of the following pairs of measurements could be correct for the lengths of the other two sides of the triangle? (Note: A² + B² = C²)

• A. 5 inches, 12 inches
• B. 2.5 inches, 6 inches
• C. 2.5 inches, 4 inches
• D. 5 inches, 8 inches

Correct answer: A

Rationale: The correct answer is A. Using the Pythagorean theorem (A² + B² = C²), we substitute the values: 5² + 12² = 13². This simplifies to 25 + 144 = 169, which is true. Therefore, 5 inches and 12 inches could be the lengths of the other two sides. Choices B, C, and D do not satisfy the Pythagorean theorem, making them incorrect options.

5. Simplify the following expression: 5/9 × 15/36

• A. 5/36
• B. 8/27
• C. 10/17
• D. 15/27

Correct answer: A

Rationale: To simplify the given expression, multiply the numerators together and the denominators together. 5/9 × 15/36 = (5 × 15) / (9 × 36) = 75 / 324. Now, simplify the resulting fraction by finding the greatest common divisor (GCD) of 75 and 324, which is 3. Divide both the numerator and denominator by 3 to get the simplified fraction: 75 ÷ 3 / 324 ÷ 3 = 25 / 108. Therefore, the simplified form of 5/9 × 15/36 is 25/108, which is equivalent to 5/36. Choice A, 5/36, is the correct answer. Choice B, 8/27, is incorrect as it does not match the simplified form of the expression. Choice C, 10/17, is unrelated and does not result from the given multiplication. Choice D, 15/27, does not correspond to the simplification of the given expression.

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