ATI TEAS 7
ATI TEAS Math Practice Test
1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?
- A. 0.96 hours
- B. 6.44 hours
- C. 6.69 hours
- D. 6.97 hours
Correct answer: D
Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.
2. A sign stating 'Do Not Enter' is in the shape of a square with side lengths of 75 centimeters. What is the area in square centimeters?
- A. 150
- B. 300
- C. 5,325
- D. 5,625
Correct answer: D
Rationale: The formula for the area of a square is given by the square of its side length: Area = side × side. For this problem, the side length of the square is 75 centimeters. To find the area, you multiply 75 by itself: 75 × 75 = 5,625 square centimeters. Thus, the area of the square is 5,625 cm². This shows that option D is correct. Choices A, B, and C are incorrect as they do not correspond to the correct calculation of the area of a square with a side length of 75 centimeters.
3. A set of patients is divided into groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Order the groups from smallest to largest.
- A. Alpha, Beta, Gamma
- B. Alpha, Gamma, Beta
- C. Gamma, Alpha, Beta
- D. Gamma, Beta, Alpha
Correct answer: C
Rationale: To determine the order from smallest to largest groups, we look at the fractions representing the groups. Group Gamma has 1/6, which is the smallest fraction, followed by Group Alpha with 1/2, and Group Beta with 1/3 being the largest fraction. So, the correct order is Gamma, Alpha, Beta. Choice A is incorrect because it lists Alpha, Beta, Gamma, which is the reverse order. Choice B is incorrect as it lists Alpha, Gamma, Beta, which is also incorrect. Choice D is incorrect as it lists Gamma, Beta, Alpha, which is not the correct order based on the fractions provided.
4. Which of the following is NOT a way to write 40 percent of N?
- A. 0.4N
- B. N/40
- C. 2/5 N
- D. 40N/100
Correct answer: B
Rationale: The correct answer is B: N/40. To find 40% of N, you multiply N by 0.4, so 0.4N is the correct representation. Choice B, N/40, is incorrect because dividing N by 40 does not give you 40% of N. Choice C, 2/5 N, is equivalent to 40% of N since 2/5 is the same as 40% when simplified. Choice D, 40N/100, is also correct since 40% can be represented as 40/100, which simplifies to 0.4, making 40N/100 another valid way to write 40% of N.
5. In a study about anorexia conducted on 100 patients, where 70% were women, and 10% of the men were overweight as children, how many male patients in the study were NOT overweight as children?
- A. 3
- B. 10
- C. 27
- D. 30
Correct answer: C
Rationale: Out of the 100 patients, 30% were men (100 - 70% women), hence 30 men. Since 10% of the men were overweight as children (10% of 30 is 3), the remaining men (30 - 3) were NOT overweight as children, which equals 27. Therefore, the correct answer is 27. Choices A, B, and D are incorrect because they do not reflect the accurate calculation of the number of male patients who were NOT overweight as children.
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