Nursing Elites

1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

2. Which of the following percentages is equivalent to the fraction 3/4?

• A. 57%
• B. 7.50%
• C. 65%
• D. 75%

Correct answer: D

Rationale: To convert a fraction to a percentage, you multiply the fraction by 100. In this case, 3/4 * 100% = 75%. Therefore, the correct answer is D. Choice A (57%) is incorrect as it does not represent the fraction 3/4. Choice B (7.50%) is incorrect as it is not the equivalent percentage of 3/4. Choice C (65%) is incorrect as it does not match the percentage value of 3/4.

3. University Q has an extremely competitive nursing program. Historically, 3/4 of the students in each incoming class major in nursing, but only 1/3 of those who major in nursing actually complete the program. If this year’s incoming class has 100 students, how many students will complete the nursing program?

• A. 75
• B. 20
• C. 25
• D. 5

Correct answer: C

Rationale: Out of 100 students, 3/4 major in nursing, which is 75 students (100 * 3/4 = 75). Among these 75 students, only 1/3 will complete the program. Therefore, 1/3 of 75 is 25. Hence, 25 students will complete the nursing program. Choice A (75) is incorrect because this represents the number of students majoring in nursing, not completing the program. Choices B (20) and D (5) are incorrect as they do not align with the calculation based on the given fractions and total number of students.

4. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

• A. (1.8, 3.6) and (-1.8, -3.6)
• B. (1.8, -3.6) and (-1.8, 3.6)
• C. (1.3, 2.6) and (-1.3, -2.6)
• D. (-1.3, 2.6) and (1.3, -2.6)

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

5. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

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