Nursing Elites

1. Robert secures three new clients every eight months. After how many months has he secured 24 new clients?

• A. 64
• B. 58
• C. 52
• D. 66

Correct answer: C

Rationale: To determine the number of months it takes for Robert to secure 24 new clients, we set up a proportion: 3 clients / 8 months = 24 clients / x months. Cross multiplying gives 3x = 8 * 24. Solving for x results in x = 64 / 3 = 52. Therefore, after 52 months, Robert has secured 24 new clients. Choice A (64) is incorrect as it miscalculates the solution. Choices B (58) and D (66) are also incorrect as they do not reflect the accurate calculation based on the given information.

2. What is the result of adding 1/6 and 1/2, expressed in reduced form?

• A. 9/7
• B. 1/3
• C. 31/36
• D. 3/5

Correct answer: B

Rationale: To add 1/6 and 1/2, you need a common denominator, which is 6. So, 1/6 + 3/6 = 4/6. Simplifying 4/6 gives 2/3, which is the correct answer (1/3). Choices A, C, and D are incorrect as they do not represent the correct sum of the fractions 1/6 and 1/2.

3. The force applied is directly proportional to the stretch of a coil. If a force of 132 Newtons stretches a coil 0.07 meters, what force would be needed to stretch a coil 0.1 meter? Round your answer to the nearest tenth.

• A. 92.4 Newtons
• B. 1885.7 Newtons
• C. 188.6 Newtons
• D. 136.0 Newtons

Correct answer: C

Rationale: To find the force needed to stretch the coil 0.1 meters, we can set up a proportion based on the given information. The initial force and stretch are in direct proportion, so we can use this relationship to determine the unknown force. (132 N / 0.07 m) = X / 0.1 m. Cross-multiplying, we get 132 N * 0.1 m / 0.07 m = 188.57 N, which rounds to 188.6 N. Therefore, the correct answer is 188.6 Newtons. Choice A is incorrect as it does not match the calculated answer. Choice B is significantly higher and does not align with the proportional relationship. Choice D is close but does not account for the correct rounding as specified in the question.

4. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

• A. 4
• B. 7
• C. 8
• D. 13

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

5. Given the double bar graph shown below, which of the following statements is true?

• A. Group A is negatively skewed, while Group B is approximately normal.
• B. Group A is positively skewed, while Group B is approximately normal.
• C. Group A is approximately normal, while Group B is negatively skewed.
• D. Group A is approximately normal, while Group B is positively skewed.

Correct answer: B

Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.

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