Nursing Elites

1. Why is polarity the most important characteristic of water?

• A. the results of the polarity are hydrogen bonding, a high specific heat value, and its versatile solvent properties
• B. the results of the polarity are covalent bonding, a low specific heat value, and its versatile solvent properties
• C. the results of the polarity are ionic bonding, a high specific heat value, and its versatile solvent properties
• D. the results of the polarity are hydrogen bonding, a low specific heat value, and its versatile solvent properties

Correct answer: A

Rationale: Polarity is the most important characteristic of water because it results in hydrogen bonding, a high specific heat value, and its versatile solvent properties. These unique properties enable water to form hydrogen bonds with other substances, resist temperature changes, and dissolve a wide variety of solutes, making it essential for life processes. Choice B is incorrect because water exhibits hydrogen bonding, not covalent bonding. Choice C is incorrect as water does not form ionic bonds. Choice D is incorrect because water has a high, not low, specific heat value, which is vital for its role in temperature regulation.

2. During protein synthesis, what process creates a complementary strand of RNA from a DNA template?

• A. Transcription
• B. Translation
• C. Transformation
• D. Replication

Correct answer: A

Rationale: The correct answer is 'Transcription.' During protein synthesis, transcription is the process that creates a complementary RNA strand from a DNA template. This process involves the synthesis of mRNA using DNA as a template. Choice B, 'Translation,' is incorrect as it is the process where the genetic code carried by mRNA is decoded to produce a specific polypeptide chain. Choice C, 'Transformation,' is not related to the synthesis of RNA from a DNA template. Choice D, 'Replication,' is the process of copying DNA to produce an identical DNA molecule, not RNA.

3. Which of the following is a tertiary consumer?

• A. Owl
• B. Shrew
• C. Grasshopper
• D. Wheat

Correct answer: A

Rationale: The correct answer is A, Owl. Tertiary consumers are organisms that feed on secondary consumers, which, in turn, feed on primary consumers. Owls are considered tertiary consumers because they primarily feed on animals such as rodents, which are secondary consumers. Shrew (choice B) is a secondary consumer, feeding on insects and worms, placing it at a lower trophic level than the owl. Grasshopper (choice C) is a primary consumer, feeding on plants. Wheat (choice D) is not a consumer in the food chain but a plant.

4. Which structure might be described as a core of nucleic acid surrounded by a protein coat?

• A. RNA
• B. Virus
• C. Blue-green alga
• D. Saprophyte

Correct answer: B

Rationale: A virus can be described as a core of nucleic acid (either RNA or DNA) surrounded by a protein coat, known as a capsid. This structure distinguishes viruses from other microorganisms such as blue-green algae (Cyanobacteria), fungi known as saprophytes, or individual RNA molecules. Viruses depend on a host cell to replicate and are considered non-living entities due to their inability to carry out metabolic functions independently.

5. Huntington’s disease is carried on the dominant allele. In a situation where two heterozygous parents have the disease, what percentage of their offspring are predicted to be disease-free?

• A. 0%
• B. 25%
• C. 50%
• D. 100%

Correct answer: B

Rationale: In this scenario, both parents are heterozygous for Huntington's disease, meaning each carries one dominant allele (representing the disease) and one recessive allele (representing no disease). When they have offspring, there is a 25% chance that each child will inherit two recessive alleles, making them disease-free. The Punnett square for two heterozygous parents (Hh x Hh) yields a 25% probability of offspring being homozygous recessive (hh) and therefore disease-free. Choice A (0%) is incorrect because there is a possibility of disease-free offspring. Choice C (50%) is incorrect as it represents the likelihood of being a carrier. Choice D (100%) is incorrect as all offspring will not be disease-free in this scenario.

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