ATI TEAS 7
Practice Math TEAS TEST
1. Which of the following options correctly orders the numbers below from least to greatest? 235.971, 145.884, -271.906, -193.823
- A. -271.906, -193.823, 145.884, 235.971
- B. -271.906, 235.971, -193.823, 145.884
- C. 145.884, -193.823, 235.971, -271.906
- D. -193.823, -271.906, 145.884, 235.971
Correct answer: A
Rationale: To correctly order the numbers from least to greatest, we start with the smallest number, which is -271.906, followed by -193.823, 145.884, and finally 235.971. Therefore, the correct order is -271.906, -193.823, 145.884, 235.971. Choice A is correct. Choice B is incorrect as it incorrectly places 235.971 before -193.823. Choice C is incorrect as it starts with the largest number, 145.884. Choice D is incorrect as it starts with -193.823, which is not the smallest number in the list.
2. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?
- A. 0.96 hours
- B. 6.44 hours
- C. 6.69 hours
- D. 6.97 hours
Correct answer: D
Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.
3. Robert plans to drive 1,800 miles. His car gets 30 miles per gallon, and his tank holds 12 gallons. How many tanks of gas will he need for the trip?
- A. 4 tanks
- B. 5 tanks
- C. 6 tanks
- D. 7 tanks
Correct answer: B
Rationale: To calculate how many gallons of gas Robert needs for the 1,800-mile trip, divide the total distance by the car's mileage per gallon: 1,800 miles ÷ 30 mpg = 60 gallons. Since his tank holds 12 gallons, Robert will need 60 gallons ÷ 12 gallons per tank = 5 tanks of gas for the trip. Choice A (4 tanks), Choice C (6 tanks), and Choice D (7 tanks) are incorrect as they do not correctly calculate the number of tanks needed based on the car's mileage and tank capacity.
4. How can you distinguish between these three types of graphs - scatterplots: Quadratic, Exponential, Linear?
- A. Linear: straight line; Quadratic: U-shape; Exponential: rises or falls quickly in one direction
- B. Linear: curved line; Quadratic: straight line; Exponential: horizontal line
- C. Linear: zigzag line; Quadratic: U-shape; Exponential: flat line
- D. Linear: straight line; Quadratic: W-shape; Exponential: vertical line
Correct answer: A
Rationale: To differentiate between the three types of graphs - scatterplots, a linear graph will display a straight line, a quadratic graph will have a U-shape, and an exponential graph will show a rapid rise or fall in one direction. Choice B is incorrect because linear graphs are represented by straight lines, not curved lines. Choice C is incorrect as linear graphs do not exhibit zigzag patterns, and exponential graphs do not typically result in flat lines. Choice D is incorrect because quadratic graphs form a U-shape, not a W-shape, and exponential graphs do not represent vertical lines.
5. Which proportion yields a different number for the unknown compared to the others?
- A. 2/3 = x/6
- B. 4/5 = x/10
- C. 3/4 = x/8
- D. 5/6 = x/12
Correct answer: D
Rationale: To find the value of x in each proportion, cross multiply. For proportion A, x = 4; for B, x = 8; for C, x = 6; and for D, x = 10. Hence, proportion D yields a different value for x compared to the others. Choices A, B, and C all result in unique values for x, but these values are distinct from the value obtained in proportion D.
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