ATI TEAS 7
Math Practice TEAS Test
1. In a fraction, which number is the numerator and which is the denominator?
- A. Numerator: top, Denominator: bottom
- B. Numerator: bottom, Denominator: top
- C. Numerator: left, Denominator: right
- D. Numerator: right, Denominator: left
Correct answer: A
Rationale: The correct answer is A: 'Numerator: top, Denominator: bottom.' In a fraction, the numerator is the top number, representing the part of the whole being considered, while the denominator is the bottom number, indicating the total number of equal parts into which the whole is divided. Choices B, C, and D are incorrect because they provide inaccurate descriptions of the numerator and denominator positions in a fraction.
2. Shawna buys 5 gallons of paint. If she uses 2/5 of it on the first day, how much paint does she have left?
- A. 3 gallons
- B. 2 gallons
- C. 1 gallon
- D. 0.5 gallons
Correct answer: A
Rationale: To find out how much paint Shawna uses on the first day, calculate 2/5 * 5 = 2 gallons. Subtracting the amount used from the total amount gives us 5 - 2 = 3 gallons remaining. Therefore, Shawna has 3 gallons of paint left after using 2 gallons on the first day. Choice A is correct. Choices B, C, and D are incorrect because she has more paint left than the options presented.
3. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?
- A. Histogram
- B. Pie chart
- C. Bar graph
- D. Scatter plot
Correct answer: A
Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.
4. A rectangular solid box has a square base with a side length of 5 feet and a height of h feet. If the volume of the box is 200 cubic feet, which of the following equations can be used to find h?
- A. 5h = 200
- B. 5h² = 200
- C. 25h = 200
- D. h = 200 ÷ 5
Correct answer: C
Rationale: The volume formula for a rectangular solid is V = l × w × h. In this case, the length and width are both 5 feet. Substituting the values into the formula gives V = 5 × 5 × h = 25h = 200. Therefore, h = 200 ÷ 25 = 8. Option A is incorrect because the product of length, width, and height is not directly equal to the volume. Option B is incorrect as squaring the height is not part of the volume formula. Option D is incorrect as it oversimplifies the relationship between height and volume, not considering the base dimensions.
5. Solve the following equation: 3(2y+50)−4y=500
- A. y = 125
- B. y = 175
- C. y = 150
- D. y = 200
Correct answer: B
Rationale: To solve the equation 3(2y+50)−4y=500, first distribute to get 6y+150−4y=500. Combining like terms results in 2𝑦 + 150 = 500. By subtracting 150 from both sides, we get 2y = 350. Dividing by 2 gives y = 175. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not correctly follow the steps of distributing, combining like terms, and isolating the variable to solve for y.
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