ATI TEAS 7
Math Practice TEAS Test
1. In a fraction, which number is the numerator and which is the denominator?
- A. Numerator: top, Denominator: bottom
- B. Numerator: bottom, Denominator: top
- C. Numerator: left, Denominator: right
- D. Numerator: right, Denominator: left
Correct answer: A
Rationale: The correct answer is A: 'Numerator: top, Denominator: bottom.' In a fraction, the numerator is the top number, representing the part of the whole being considered, while the denominator is the bottom number, indicating the total number of equal parts into which the whole is divided. Choices B, C, and D are incorrect because they provide inaccurate descriptions of the numerator and denominator positions in a fraction.
2. Solve the equation for the unknown. 3x + 2 = 20
- A. x = 2
- B. x = 4
- C. x = 6
- D. x = 8
Correct answer: C
Rationale: Simplify the equation step by step: Subtract 2 from both sides: 3x + 2 - 2 = 20 - 2 3x = 18 Divide both sides by 3: x = 18 ÷ 3 x = 6 Therefore, the correct answer is C (x = 6).
3. Approximately how many people voted for the proposition if 9.5% of the town's population of 51,623 voted for it in a municipal election?
- A. 3,000
- B. 5,000
- C. 7,000
- D. 10,000
Correct answer: B
Rationale: To find the approximate number of people who voted for the proposition, multiply the town's population by the percentage that voted for it. 9.5% of 51,623 is about 0.095 * 51,623 ≈ 4,904. Rounded to the nearest thousand, this gives an estimate of 5,000 people. Therefore, choice B, '5,000,' is the correct answer. Choices A, C, and D are incorrect as they do not align with the calculated estimation.
4. In the winter of 2006, 6 inches of snow fell in Chicago, IL. The following winter, 3 inches of snowfall fell in Chicago. What was the percent decrease in snowfall in Chicago between those two winters?
- A. 69.40%
- B. 59.00%
- C. 41.00%
- D. 24.70%
Correct answer: C
Rationale: To calculate the percent decrease in snowfall between the two winters, use the formula: Percent Decrease = ((Initial Value - Final Value) / Initial Value) * 100. In this case, the initial value is 6 inches and the final value is 3 inches. Plug these values into the formula: ((6 - 3) / 6) * 100 = (3 / 6) * 100 = 0.5 * 100 = 50%. Therefore, the correct answer is 50%, which is not listed among the choices provided. Among the given choices, the closest percentage is 41.00%, which corresponds to choice C.
5. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36
- A. 5
- B. 4
- C. 7
- D. 3
Correct answer: C
Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.
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