Nursing Elites

1. During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?

• A. 15 shifts
• B. 14 shifts
• C. 16 shifts
• D. 17 shifts

Correct answer: B

Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).

2. Which of the following numbers has the greatest value?

• A. 1.4378
• B. 1.07548
• C. 1.43592
• D. 0.89409

Correct answer: B

Rationale: To determine the number with the greatest value among the options, focus on the digit in the tenths place. In this case, 1.07548 has the highest value as it has the digit 7 in the tenths place. Comparing this to the other numbers, 1.4378, 1.43592, and 0.89409 have 4, 3, and 8 in the tenths place, respectively. Therefore, 1.07548 is the number with the greatest value as it has the highest digit in the tenths place.

3. As part of a study, a set of patients will be divided into three groups: 1/2 of the patients will be in Group Alpha, 1/3 of the patients will be in Group Beta, and 1/6 of the patients will be in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.

• A. Group Alpha, Group Beta, Group Gamma
• B. Group Alpha, Group Gamma, Group Beta
• C. Group Gamma, Group Alpha, Group Beta
• D. Group Gamma, Group Beta, Group Alpha

Correct answer: C

Rationale: The correct order from smallest to largest number of patients in each group is Group Gamma (1/6), Group Alpha (1/2), and Group Beta (1/3). Group Gamma has the smallest fraction of patients, followed by Group Alpha and then Group Beta. Therefore, choice C, 'Group Gamma, Group Alpha, Group Beta,' is the correct answer. Choices A, B, and D are incorrect because they do not follow the correct order based on the fractions of patients assigned to each group.

4. Dr. Lee observed that 30% of all his patients developed an infection after taking a certain antibiotic. He further noticed that 5% of that 30% required hospitalization to recover from the infection. What percentage of Dr. Lee's patients were hospitalized after taking the antibiotic?

• A. 1.50%
• B. 5%
• C. 15%
• D. 30%

Correct answer: A

Rationale: To find the percentage of Dr. Lee's patients hospitalized after taking the antibiotic, we need to calculate 30% of 5%. First, convert 30% and 5% to decimals: 30% = 0.30 and 5% = 0.05. Multiply 0.30 by 0.05 to get 0.015. To convert 0.015 to a percentage, multiply by 100, resulting in 1.5%. Therefore, only 1.50% of Dr. Lee's patients were hospitalized after taking the antibiotic. Choice A is correct. Choice B (5%) is incorrect as it represents the percentage of patients who developed an infection and not those hospitalized. Choices C (15%) and D (30%) are also incorrect percentages as they do not accurately reflect the proportion of hospitalized patients in this scenario.

5. Gordon purchased a television that was 30% off its original price of $472. What was the sale price?

• A. 141.60
• B. 225.70
• C. 305.30
• D. 330.40

Correct answer: D

Rationale: To find the sale price after a 30% discount, you first calculate the discount amount which is 30% of $472. 30% of $472 is $141.60. To find the sale price, you subtract the discount amount from the original price: $472 - $141.60 = $330.40. Therefore, the sale price of the television after a 30% discount would be $330.40. Choices A, B, and C are incorrect as they do not accurately reflect the calculated sale price after the discount.

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