which element is used in fluorescent lamps and emits ultraviolet light when excited

ATI TEAS 7

TEAS Test 7 science

1. Which element is used in fluorescent lamps and emits ultraviolet light when excited?

A. Mercury
B. Neon
C. Argon
D. Krypton

Correct answer: A

Rationale: Mercury is the correct element used in fluorescent lamps to emit ultraviolet light when excited. When an electric current passes through the mercury vapor inside the lamp, it generates ultraviolet (UV) light. This UV light then excites the phosphors coated on the inner surface of the lamp, causing them to emit visible light. Neon, argon, and krypton are not commonly used in fluorescent lamps for this purpose. Neon is primarily used in neon signs, argon is used in incandescent and fluorescent bulbs for inertia gas, and krypton is mainly used in certain types of specialized light bulbs for its specific properties.

2. What is the difference between a homozygous recessive genotype and a homozygous dominant genotype?

A. Both have the same phenotype, but different genotypes.
B. Both have the same genotype, but different phenotypes.
C. Homozygous recessive has two dominant alleles, while homozygous dominant has two recessive alleles.
D. Homozygous recessive has two identical recessive alleles, while homozygous dominant has two identical dominant alleles.

Correct answer: D

Rationale: - Homozygous recessive genotype refers to an individual having two identical recessive alleles for a particular gene (e.g., rr for a trait where r represents the recessive allele). - Homozygous dominant genotype refers to an individual having two identical dominant alleles for a particular gene (e.g., RR for a trait where R represents the dominant allele). - The difference between the two genotypes lies in the specific alleles present in each case, with homozygous recessive having two recessive alleles and homozygous dominant having two dominant alleles. - This genetic difference results in different phenotypes being expressed, as the dominant allele typically masks the expression of the recessive allele in heterozygous individuals.

3. An investigator wishes to test the effect of temperature on the durability of a certain material. He places five blocks of this material in a sunny area in a meadow and five more in a cold area high in the mountains. He then monitors them over time. What is the main problem with this experiment?

A. Ten subjects are far too small a number to obtain effective results.
B. It is impossible to control for the fact that the blocks in the mountains were placed later.
C. There are too many variables that are not being controlled for.
D. Nothing is wrong with this experiment; this demonstrates good experimental procedure.

Correct answer: C

Rationale: The main problem with this experiment is that there are too many variables that are not being controlled for. The investigator is only changing one variable (temperature) while there are other variables at play such as humidity, exposure to light, and potential differences in the material itself. Without controlling or accounting for these additional variables, it would be difficult to determine if any observed differences in durability are solely due to temperature. Choice A is incorrect because the issue is not solely about the number of subjects but about the lack of control over variables. Choice B is not the main problem as the order of placement may not significantly impact the results. Choice D is incorrect as the experiment lacks proper control over variables, which is a crucial aspect of good experimental procedure.

4. What is the process by which a cell divides into two or more new cells?

A. Mitosis
B. Meiosis
C. Both mitosis and meiosis
D. None of the above

Correct answer: A

Rationale: Mitosis is the process by which a cell divides into two identical daughter cells. This type of cell division is essential for growth, repair, and maintenance of multicellular organisms. Meiosis, on the other hand, is a type of cell division that produces gametes (sperm and egg cells) with half the number of chromosomes as the parent cell. Meiosis does not directly result in the formation of new cells, as it is specifically geared towards the production of reproductive cells. Therefore, the correct answer is A. Option C, stating both mitosis and meiosis, is incorrect because meiosis is not involved in the general process of cell division to produce new cells; it is specialized for gamete formation. Option D is incorrect because mitosis is indeed the process responsible for cell division in which one cell divides into two daughter cells, making it the accurate choice for this question.

5. What is the normal (complete) flow of blood through the heart?

A. Right atrium â†’ lungs â†’ left atrium â†’ body
B. Left atrium â†’ left ventricle â†’ body â†’ right atrium
C. Right atrium â†’ right ventricle â†’ lungs â†’ left atrium â†’ left ventricle â†’ aorta â†’ body
D. Right ventricle â†’ left ventricle â†’ body

Correct answer: C

Rationale: The correct flow of blood through the heart starts with the right atrium receiving deoxygenated blood from the body, followed by the right ventricle pumping blood to the lungs for oxygenation. Oxygenated blood then returns to the heart through the left atrium, then passes to the left ventricle which pumps it out to the body through the aorta. This flow ensures that blood is properly oxygenated before circulating through the body. Choice A is incorrect as the blood does not go directly from the left atrium to the body, skipping the left ventricle. Choice B is incorrect as it does not follow the correct flow sequence in the heart. Choice D is incorrect as it does not include the full pathway of blood through the heart.