Nursing Elites

1. When the weights of the newborn babies are graphed, the distribution of weights is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?

• A. Uniform
• B. Bimodal
• C. Bell-shaped
• D. Skewed right

Correct answer: C

Rationale: The correct answer is C: Bell-shaped. A symmetric distribution with a single peak is characteristic of a bell-shaped distribution, also known as a normal distribution. This distribution forms a symmetrical, bell-like curve when graphed. Choice A, 'Uniform,' would describe a distribution where all values have equal probability. Choice B, 'Bimodal,' would indicate a distribution with two distinct peaks. Choice D, 'Skewed right,' suggests a distribution where the tail on the right side is longer or more pronounced, unlike the symmetrical bell-shaped distribution described in the question.

2. Simplify the expression 3x - 5x + 2.

• A. -2x + 2
• B. -8x
• C. 2x + 2
• D. -2x

Correct answer: D

Rationale: When simplifying the expression 3x - 5x + 2, start by combining like terms. -5x is subtracted from 3x to give -2x. Adding 2 at the end gives the simplified expression -2x. Therefore, the correct answer is -2x. Choice A, -2x + 2, incorrectly adds 2 at the end. Choice B, -8x, incorrectly combines the coefficients of x without considering the constant term. Choice C, 2x + 2, incorrectly adds the coefficients of x without simplifying.

3. If Hannah spends at least $16 on 4 packages of coffee, which of the following inequalities represents the possible costs?

• A. 16 ≥ 4p
• B. 16 < 4p
• C. 16 > 4p
• D. 16 ≤ 4p

Correct answer: D

Rationale: To represent the relationship between the number of packages of coffee and the minimum cost, the inequality can be written as 4p ≥ 16 (cost is at least $16). This inequality can also be expressed as 16 ≤ 4p, which reads as the cost being less than or equal to $16. Therefore, the correct answer is D. Choice A (16 ≥ 4p) implies that the cost can be greater than or equal to $16, which does not align with the statement that Hannah spends at least $16. Choice B (16 < 4p) suggests that the cost is less than $16, which contradicts the given information. Choice C (16 > 4p) indicates that the cost is greater than $16, which is not accurate based on the scenario provided.

4. The phone bill is calculated each month using the equation C = 50 + 75D. The cost of the phone bill per month is represented by C, and D represents the gigabytes of data used that month. What is the value and interpretation of the slope of this equation?

• A. 75 dollars per gigabyte
• B. 75 gigabytes per day
• C. 50 dollars per day
• D. 50 dollars per gigabyte

Correct answer: A

Rationale: The slope of the equation C = 50 + 75D is 75. This means that for each additional gigabyte used (represented by D), the cost (represented by C) increases by 75 dollars. Therefore, the correct interpretation of the slope is that it is 75 dollars per gigabyte. Choice B, 75 gigabytes per day, is incorrect as the slope does not represent the rate of data usage per day. Choice C, 50 dollars per day, is incorrect as it does not reflect the relationship between gigabytes used and the cost. Choice D, 50 dollars per gigabyte, is incorrect as it does not match the slope value of 75 in the equation.

5. A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?

• A. 24
• B. 28
• C. 36
• D. 38

Correct answer: C

Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.

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