Nursing Elites

1. What is the mode of the data set: 2, 3, 3, 4, 4, 4, 5?

• A. 2
• B. 3
• C. 4
• D. 5

Correct answer: C

Rationale: The mode of a data set is the value that appears most frequently. In this data set (2, 3, 3, 4, 4, 4, 5), the number 4 appears three times, which is more frequent than any other number in the set. Therefore, the correct answer is 4. Choice A (2), B (3), and D (5) do not appear as frequently as 4 in the data set, so they are not the mode.

2. Express 18/5 as a reduced mixed number.

• A. 3 3/5
• B. 3 1/15
• C. 3 1/18
• D. 3 1/54

Correct answer: A

Rationale: To convert the improper fraction 18/5 to a mixed number, divide 18 by 5. The quotient is 3 with a remainder of 3, which translates to 3 3/5. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not accurately represent the conversion of 18/5 to a mixed number.

3. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

4. A car dealership’s commercials claim that this year’s models are 20% off the list price, plus they will pay the first 3 monthly payments. If a car is listed for $26,580, and the monthly payments are set at $250, what is the total potential savings?

• A. $1,282
• B. $5,566
• C. $6,066
• D. $20,514

Correct answer: C

Rationale: To calculate the total potential savings: First, find the 20% discount on the list price of $26,580: 0.20 × $26,580 = $5,316. Then, determine the savings over the first 3 months of payments: 3 months × $250/month = $750. Add the discount and the monthly payment savings to get the total potential savings: $5,316 + $750 = $6,066. Therefore, the correct answer is $6,066. Choice A, $1,282, is incorrect because it does not account for the total savings from both the discount and the monthly payments. Choice B, $5,566, is incorrect as it miscalculates the total savings by excluding the savings from the monthly payments. Choice D, $20,514, is incorrect as it does not consider the discount and only focuses on the list price.

5. Which of the following is not a negative value?

• A. (−3)(−1)(2)(−1)
• B. 14 – 7 + (−7)
• C. 7 – 10 + (−8)
• D. −5(−2)(−3)

Correct answer: B

Rationale: To identify the negative value, simplify each expression. A) simplifies to 6 which is positive. B) simplifies to 0 which is neither positive nor negative. C) simplifies to -11 which is negative. D) simplifies to -30 which is negative. Therefore, only choice B results in a non-negative value, making it the correct answer.

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