ATI TEAS 7
TEAS Test Math Prep
1. Adrian measures the circumference of a circular picture frame with a radius of 3 inches. Which of the following is the best estimate for the circumference of the frame?
- A. 12 inches
- B. 16 inches
- C. 18 inches
- D. 24 inches
Correct answer: C
Rationale: To calculate the circumference of a circle, use the formula 2πr, where r is the radius. In this case, with a radius of 3 inches, the estimated circumference would be 2 x π x 3 = 6π ≈ 18.85 inches. Therefore, the best estimate for the circumference of the frame is 18 inches (Choice C). Choice A (12 inches) is too small as it corresponds to the diameter rather than the circumference. Choice B (16 inches) and Choice D (24 inches) are also incorrect as they do not reflect the accurate calculation based on the given radius.
2. Given a double bar graph, which statement is true about the distributions of Group A and Group B?
- A. Group A is negatively skewed, Group B is normal.
- B. Group A is positively skewed, Group B is normal.
- C. Group A is positively skewed, Group B is neutral.
- D. Group A is normal, Group B is negatively skewed.
Correct answer: B
Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.
3. What percentage of rainfall received during this timeframe is received during the month of October?
- A. 13.50%
- B. 15.10%
- C. 16.90%
- D. 17.7%
Correct answer: D
Rationale: To determine the percentage of rainfall received during the month of October, we must first calculate the total rainfall for October and the total rainfall for the entire timeframe. Given that the total rainfall for October is 18.9 inches and the total rainfall from January to November is 106.3 inches, we can proceed with the calculation. The percentage is calculated as (18.9/106.3) x 100 = 17.7%. Therefore, the correct answer is D, 17.7%. Choice A (13.50%), Choice B (15.10%), and Choice C (16.90%) are incorrect as they do not align with the accurate calculation based on the provided data.
4. Margery is planning a vacation, and her round-trip airfare will cost $572. Her hotel costs $89 per night, and she will be staying at the hotel for five nights. She has allotted a total of $150 for sightseeing and expects to spend about $250 on meals. She will receive a 10% discount on the hotel price after the first night. What is the total amount Margery expects to spend on her vacation?
- A. $1,328.35
- B. $1,373.50
- C. $1,381.40
- D. $1,417.60
Correct answer: C
Rationale: To calculate Margery's total expenses: Airfare ($572) + Hotel ($89 * 5 nights) = $572 + $445 = $1017. After the first night's stay, Margery receives a 10% discount on the remaining four nights, making the total hotel cost $445 - (10% of $89) = $445 - $8.90 = $436.10. Adding sightseeing ($150) and meals ($250) to the total gives $1017 + $150 + $250 = $1417. Margery's expected expenses are $1417, not $1381.40 as stated in the original rationale. Therefore, the correct answer is $1,417.60 (Option D).
5. Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?
- A. 128 pounds
- B. 150 pounds
- C. 175 pounds
- D. 180 pounds
Correct answer: B
Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.
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